Converting Binary Digits To Hex

[JohnBlaze]

converting 8bit binary into 2 digit hex

Any ideas on how to do this?
im starting it now but going in the direction of using arrays

will be back to post my code

thanks.

[MiiNiPaa]

Each 4 binary digits can be represented by one hex digit: so 77₁₀ = 100 1101₂ = 4D₁₆
What you must do depends how you will get your statements. I would just get number in string, parse it by stoi() and output it into string steam using hex manipulator:

#include <iostream>
#include <iomanip>
#include <sstream>

int main()
{
    std::string temp;
    std::getline(std::cin, temp);
    int x = stoi(temp, 0, 2);
    std::cout << std::hex << x << std::endl; //To output
    std::stringstream out;
    out << std::hex << x;
    temp = out.str(); //Temp now has number in hex representation
    std::cout << temp;
}

[JohnBlaze]

thank you, honestly is meant to do type it the other way around lol

Convert hex to 8 bit binary (stupid me)
i think then you would need to use arrays

,sorry :(

[MiiNiPaa]

Nope

#include <iostream>
#include <bitset>
#include <sstream>

int main()
{
    std::string temp;
    std::getline(std::cin, temp);
    std::bitset<8> y(stoi(temp, 0, 16));
    std::cout << y << std::endl; //To output
    std::stringstream out;
    out << y;
    temp = out.str(); //Temp now has number in hex representation
    std::cout << temp;
}

Or without bitset and leading zeroes:

#include <iostream>
#include <sstream>
#include <algorithm>
#include <iterator>

int main()
{
    std::string temp;
    std::getline(std::cin, temp);
    unsigned int x(stoi(temp, 0, 16)); //Do not work with negative values
    std::stringstream y;
    while (x!=0) {
        y << (x&1);
        x >>= 1;
    }
    temp = y.str();
    std::copy(temp.rbegin(), temp.rend(), std::ostream_iterator<char>(std::cout));
}

[JohnBlaze]

how would this be done using arrays?