The switching to a different Pac will not display

[gyneisler]

#include<iostream>
#include<cctype>
using namespace std;

int main()
{
	char package;
	double units;
	double fees_a, fees_b, fees_c;
	int A, B, C, Q;
	double pac_a,pac_b, pac_c;
	do
	{
	 do
		{
	cout <<"Which pakage are you shopping for?:Please enter A, B, C, or Q to quit."<< endl;
	cin>> package;
	cout<<"How many message units?:"<<endl;
	cin>>units;
		 package = toupper(package);
	}while(package !='A' && package !='B' &&	package !='C' && package !='Q');
	}while(units < 0 || units >672);
			switch(package)
	{
		case 'A':
		
				
		if (units <=10)
		{
		fees_a = 9.95;
		cout<<"The charges are:"<< fees_a<< endl;
		}
	else
	{
		(units > 10);
		
		fees_a = (units - 10) * 2 + 9.95;
		cout<<"The charges are:"<< fees_a<< endl;
		break;
		
		case 'B':
		
			
      if (units <= 20)
		{
		fees_b = 19.95;
		cout<<"The charges are:"<< fees_b<< endl;
      }
	 else (units >20);
	 {
			fees_b = ((units - 20) + 19.95);
			cout<<"The charges are:"<< fees_b<< endl;
		}	
			break;
			case 'C':
		        
			fees_c = 39.95;
			
			cout<<"The charges are:"<< fees_c<< endl;
		
			break;
					
		case 'Q':
								
			cout<<"Thank you for using this program. Goodbye."<< endl;
			break;
			default:
			cout<<"Enter only 0 through 672."<<endl;
	
	if(fees_a < fees_b && fees_a < fees_c)
	{
		cout<<"Package A is a better plan"<< endl;
	}
	else if(fees_b < fees_c)
	{
		pac_b = (fees_a - units + 19.95) +20;
		pac_c = (fees_a - 39.95);
		
		cout<<"By switching to package B you would save:$"<<pac_b<<endl;
		cout<<"By switching to package C you would save:$"<<pac_c<<endl;
		
	}
	else
	{
		cout<<"Package C is a better plan"<<endl;			
			
		
					
		return 0;
		}
		}
		}
		}
			

[3qX21hU5]

This thread is more suited towards beginner section of this website. You might want to move it there, since you will get more help there.

[z05DSL3A]

gyneisler, It looks like you have a '}' out of place. Look at the else in case 'A':.

PS: I also recommend you spend some time learning a neater formatting style. ;0)