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its devonrevenge's birthday we had better code him something good or we are worthless people

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closed account (Dy7SLyTq)
there was talk of a game called Devon's Revenge
ah yes, my suggestion

For some reason the name reminds of that old atari game called custer's revenge i believe (i wouldnt look that up )
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Revenge on the world because he didn't get cake.
YES :D

EDIT: I looked up Devon's revenge and Custers revenge, one is gay erotica novel the other is native american girl rape game :/
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closed account (Dy7SLyTq)
well you have to pick one of those two devon
Why not just combine the two?
Its my birthday you have to surprise me .
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On the 17th I'll surprise you by doing the same thing I do everyday. Absolutely nothing.
BHXSpecter wrote:
On the 17th I'll surprise you by doing the same thing I do everyday. Absolutely nothing.


the secret to no success.
You had better be working on it.
Alright. Here is your birthday gift.
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int main()
{
      return 0;
}


There.
Damn, BHX why didn't you do this?
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Present* present()
{
    return NULL;
}
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Devon try this Tic Tac Toe game (coded in Python (Tk)).
There is currently one way to beat it (working on that).

Link: http://usandfriends.x10.mx/TicTacToePU.zip
(Run ~HOME/Production Unit/Tkinter.exe)
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if (member_of_cplusplus.present == true)
{
    allowed_life[next_member] = member_of_cplusplus.name;
    nextmember++;
}

else
{
    death_list[next_member] = member_of_cplusplus.name;
    nextmember++;
}
Hate to call you out on this devon but isn't
member_of_cplusplus.present == true

a bit redundant?
closed account (Dy7SLyTq)
no because the member could be off at testing. it should be in a while loop
Lumpkin wrote:
Damn, BHX why didn't you do this?

Because that would have took more effort to think of than I had cared to put into it.

@DTSCode
I think he means, if you can check to see it the value is true, you should be able to just say if(member_of_cplusplus.present){}else{} because if present is false then it would fail and run the else code block.


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if(true)
{
      // run if condition is true
}
else
{
      // run if condition is false
}

Doing a while loop would make it a little of a pain as you would have to enter and exit it per member. If a member isn't present the while loop would exit, but could be only an element or two into the member list, a while loop wouldn't be the right choice in this example.
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closed account (Dy7SLyTq)
but then it would only test one member
Isn't that the point?
DTSCode wrote:
but then it would only test one member

You could put the if/else block in a while loop. Using your method of a while loop would only test up until it ran into a member that wasn't here. For example, if Albatross, Disch, and you were the first three in the list and Albatross didn't bring a present it would evaluate to false and not bother reading Disch or you. So you would have to make a vector to hold the list of members. Then just an example (not actual code).
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vector<string> list;
while(!list.end())
{
    if(...)
    esle{....}
}

Just an example, so I don't know if it would work
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