How to find the column index of a matrix element

[telco]

Hello Everyone,

I am a beginner in C++.

I want to find the column index of a matrix element with given row number.

For example,

table = {{0, 2, 0, 4}, {3, 4, 0, 0.7}, {0.1, 0.9, 5, 6}}

current_row_index = 1
value = 4

Here current_row_index and value are variables. I want to find out the corresponding column index of 4.

I tried in following way, but it does not work. Can anyone please correct the code? Thank you!



for (int m = 0; m < row_size; ++m) {
for (int n = 0; n < column_size; ++n) {
if((m = current_row_index) && (table[current_row_index][n] == value))
{
value_index = n;
break;
}
else
{
break;
}


}


}

[lastchance]

You don't need to loop on m if you know the row index.

That would solve your main problem. Use ==, not =, when comparing for equality (your if statement). You also appear to be breaking out of the column loop even if the value isn't found: you don't need the "else".

Please use code tags (and post complete programs).

[jonnin]

you have assignment in your if statement, which is legal but usually wrong. (= vs ==)
does it work if you fix that?
your question is not matching your code. if row# is given why iterate it?

[telco]

Thanks for your responses. I will try with ==.

In my question, i mentioned that current_row_index and value are variables.

I gave that example to explain what i want.

But, row # is not given. It will be selected randomly.

Thank you

[jonnin]

selected randomly is given, in the sense we mean.
you say
for (int m = 0; m < row_size; ++m)
which checks every row.
if you randomly select it, the code should be
m = a_random_row;
for(all the columns of the mth row)
...

there is no point in checking to see if m is the selected row in a loop. Just use the selected row: the POINT of array like structures is the direct access, you don't need to LOOK for what you already know.

[telco]

Ok, thank you.