execl() number of args

hello, what must i write in my program to ensure that whenever i call execl, the correct number of arguments are passed into it?

example, if i write the code to pass 4 arguments into the execl(), the 5th to n arguments would be ignored. is there a way to prevent this... other than overloading?

if there is none, is there an alternative?

thanks.

bnbertha (404)

there are a whole family of exec calls, some take lists, some take vectors. It sounds like you need to use one of the vector variants e.g. execv().

theChameleon (12)

thanks for your reply... :D

This topic is archived - New replies not allowed.


		C++ : Forums : UNIX/Linux Programming : execl() number of args Search: