Last 4 Digits of SSN

[ajbernabeo]

Hey Guys, I need MAJOR help. I'm a C++ noob and I need to find out the code to read the last 4 digits of an SSN from a file. Thank so much.

[modoran]

What it is "SSN" ????

[ajbernabeo]

Social Security Number (SSN)

[modoran]

So give an example of what format this SSN have, and what is the content of the file (it contains only one SSN or more).

[ajbernabeo]

I have no format, that's why I am asking. The file can contain one SSN just to make it easy. The SSN is 10 numbers without any dashes or whitespaces. For example: 1467439678.

[S G H]

So that is simple. Open the requested files. Read in everything. Store the data from (10 - 4)th character.

Give me a guideline and I'll help you taking the right way.

[modoran]

#include <fstream>
#include <string>

using namespace std;

int main () {

string fname;
cout << "Enter file name :" << endl;
cin >> fname;

ifstream ifs;
if (!ifs.open (fname.c_str(), ios::binary)) {
cout << "failed to open the file !" << endl;
return 1;
}
char buf [11] = {0};
ifs.read (buf, 10);
string result;
result += buf[6];
result += buf[7];
result += buf[8];
result += buf[9];
cout << result << endl;
return 0;
}

I have not tested this example.

[bobdabilder]

I tweaked up modoran's example up a bit.
tweaked. thanks.

	string fname;
cout << "Enter file name :" << endl;
cin >> fname;

ifstream ifs;
int i;
string result;
char buf [11] = {0};
ifs.open(fname.c_str(), ios::binary);
if(ifs.read(buf,10))
{
	result += buf[6];
	result += buf[7];
	result += buf[8];
	result += buf[9];
	cout << "Last Four Are: ";
	cout << result << endl;
	cin >> i;
	return 1;
}
else
{
	cout << "Failed to read file";
	cin >> i;
	return 0;
}

[ajbernabeo]

Ok I found a solution to my problem that, I think, may help you....

File input will be named "Input.txt" and will contain the SSN "1252369874"

#include <iostream>
#include <fstream>
#include <iomanip>
using namespace std;

int main()

{ // Entry Point

// File Input
     ifstream fin;
     fin.open("Input.txt");
     if (!fin.good()) throw "I/O ERROR";

     // File Input Info
     int SSN;
     fin >> SSN;
     SSN = SSN % 10000;  // Changes value of INT to the number of '0' you input
                         // For example you have 999 in your file and you input 100... The output will be 99
// File Output
     ofstream fout;
     fout.open("Report.txt");
     if (!fout.good()) throw "I/O ERROR";  // By doing this skips the monitor output and goes directly to File Output

     // File Output Info
     fout << setfill('*') << setw(10) << SSN << endl;  // The setfill and setw just makes it look nice and readable     

     return 0;

} // End Point 

The File Output is "******9874"

I have tried it and it worked. Thanks Modoran for the code, but it was to long.

If you have multiple data in a File Input like:

5412369874
6541239875

DO THIS

#include <iostream>
#include <fstream>
#include <iomanip>
using namespace std;

int main()

{ // Entry Point
// File Input
     ifstream fin;
     fin.open("Input.txt");
     if (!fin.good()) throw "I/O ERROR";

     // File Input Info
     int SSN;

// File Output
     ofstream fout;
     fout.open("Repot.txt");
     if (!fout.good()) throw "I/O ERROR";

     while(!fin.eof())
     { // DO NOT put DECLARATION STATEMENTS in WHILE loop
          // File Input Info
          fin >> SSN

          // Show Last 4 Digits of SSN
          SSN = SSN % 10000;

          // File Output Info
          fout << setfill('*') << setw(10) << SSN <<endl;

     } // While

     return 0;

} // End Point 

NOTE: NEVER put Declaration Statements in a WHILE loop

Hope this will help you become fast and lazy programmers ^^