While working only when std::cout is usedI see now. Thank you for your answers. I forgot about that.
While working only when std::cout is usedIn reply to your edit, I am aware of the dangers if the numbers are large and that's why I won't use...
While working only when std::cout is usedThanks for the reply. My function is supposed to take in a decimal number and output it in the form ...
While working only when std::cout is usedI have encountered an unusual problem: I have a while(1) loop that will break after a few iterations...
Passing actual variables to a functionThank you. I haven't used C++11 before, but I'll give it a try.