Switch statements (going straight to default)

[frueda75]

#include <iostream>
using namespace std;

int main() {
int nextChoice;

cin >> nextChoice;

switch (nextChoice) {
case '0' :
cout << "Rock" << endl;
break;

case '1' :
cout << "Paper" << endl;
break;

case '2' :
cout << "Scissors" << endl;
break;

default :
cout << "Unknown" << endl;
break;
}
return 0;
}





its suppose to give me an answer depending on the number I insert it seems very basic and I'm not sure why its not working the only numbers allowed to be inputed are 1, 2 ,3.

[lastchance]

Just write
0
not
'0'
etc. in your case statements. You are comparing with ints, not chars.

[salem c]

Or char nextChoice; and leave all your cases as character constants.

Type 48 into your existing program :)

[seeplus]

Consider:

#include <iostream>
using namespace std;

int main() {
	char nextChoice {};

	cin >> nextChoice;

	switch (nextChoice) {
		case '0':
			cout << "Rock\n";
			break;

		case '1':
			cout << "Paper\n";
			break;

		case '2':
			cout << "Scissors\n";
			break;

		default:
			cout << "Unknown\n";
			break;
	}
}

or:

#include <iostream>
using namespace std;

int main() {
	int nextChoice {};

	cin >> nextChoice;

	switch (nextChoice) {
		case 0:
			cout << "Rock\n";
			break;

		case 1:
			cout << "Paper\n";
			break;

		case 2:
			cout << "Scissors\n";
			break;

		default:
			cout << "Unknown\n";
			break;
	}
}

Note to use \n instead of endl to output a new line.

There is a difference between type int and type char. 0 means an int of value 0. '0' means a char that has an ASCII value of 48.