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dangling-else problem

Sharan123 (352)
(Dangling-else Problem) State the output for each of the following when x is 9 and y is 11 and when x is 11 and y is 9. The compiler ignores the indentation in a C++ program. The C++ compiler always associates an else with the previous if unless told to do otherwise by the placement of braces {}. On first glance, you may not be sure which if and else match, so this is referred to as the “dangling-else” problem. We eliminated the indentation from the following code to make the problem more challenging. [Hint: Apply indentation conventions you’ve learned.]

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 if ( x < 10 )
if ( y > 10 )
cout << "*****" << endl;
else
cout << "#####" << endl;
cout << "$$$$$" << endl;

b)
if ( x < 10 )
{
if ( y > 10 )
cout << "*****" << endl;
}
else
{
cout << "#####" << endl;
cout << "$$$$$" << endl;
}

Solution:

a) 
x = 9, y = 11

*****
$$$$$


x = 11, y = 9

$$$$$

b)
x = 9, y = 11

*****
x = 11, y = 99

#####
$$$$$
vlad from moscow (6539)
And what is the question?
Sharan123 (352)
repost it with proper indentation
Sharan123 (352)
my confusion is like in the first part if (9<10) the if part is empty for x portion so shouldn't print anything and (11>10) for the y portion so it should print the first line of else as c++ rule if no brackets are applied so the output should be "#####" but it is "*****" and "$$$$$" which is completely opposite of what i think.
vlad from moscow (6539)
a)
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if ( x < 10 )
{
   if ( y > 10 )
   {
      cout << "*****" << endl;
   }
   else
   {
      cout << "#####" << endl;
   }
}

cout << "$$$$$" << endl;


b)
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if ( x < 10 )
{
   if ( y > 10 )
   {
      cout << "*****" << endl;
   }
}
else
{
   cout << "#####" << endl;
   cout << "$$$$$" << endl;
}

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