How do you read from file to a 3D array?

[yqD8vCM9]

1) There is a data file containing strings. You must read all the strings into a 3D array.

Is this the rright way?
So confused.
Thank You in advance.

[Josue Molina]

(deleted)

[yqD8vCM9]

Something like this

Then what are x,y,z? Rows? Columns?

[andywestken]

@defjamvan123

Your first version (with 2 loop) is correct if you want to store a 2D array of strings.

This

char myArray[x][y][z];

should be taken to be a 2D array (x by y) of char buffers (each z chars long)

If you need to store a 3D array of strings, then you'll need to either: (a) switch to using string rather than char, or (b) add another dimension.

Andy

PS Scaled down version:

#include <iostream>
#include <fstream>
using namespace std;

int main()
{
  const int x =  4;
  const int y =  3;
  const int z = 32;

  char myArray[x][y][z];

  ifstream fin("c:\\test\\arr_data.txt");

  for ( int i = 0; i < x; i++ )
  {
    for ( int j = 0; j < y; j++ )
    { 
      fin >> myArray[i][j];
    }
  }

  for ( int i = 0; i < x; i++ )
  {
    for ( int j = 0; j < y; j++ )
    { 
      cout << "myArray[" << i << "][" << j << "] = " << myArray[i][j] << endl;
    } 
  }

  return 0;
}

Reading this file in (arr_data.txt)

one   two    three
four  five   six
seven eight  nine
ten   eleven twelve

It outputs:

myArray[0][0] = one
myArray[0][1] = two
myArray[0][2] = three
myArray[1][0] = four
myArray[1][1] = five
myArray[1][2] = six
myArray[2][0] = seven
myArray[2][1] = eight
myArray[2][2] = nine
myArray[3][0] = ten
myArray[3][1] = eleven
myArray[3][2] = twelve

[yqD8vCM9]

@andywestken Thanks alot!

[andywestken]

PS

Then what are x,y,z? Rows? Columns?

For

char myArray[x][y][z];

it's an array, of x rows and y cols, of buffers of z chars

Andy