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urgently need help (while loop)

xarmzon (5)
i keep getting run time error in this program. if I input a the loop still continue but if I put a for the second time, the loop will now stop and I can't figure out the bug. I want the loop to stop if user input either a,b,c,d to m. thanks

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  // solution to question 2 chapter five

//write a menu program that  let the user
//select from a list of options, and if the
//input is not one of the options, reprint
//the list.

#include <iostream>
#include <string>
using namespace std; 

int main()
{

  string type = " ";

cout << "Welcome to xarm softdrinks shop" << endl << endl;

cout << "choose your order below! (a - n)" << endl << endl;
cout << "a - Coca-Cola \t\t b - Sprite" << endl; 
cout << "c - Fanta \t\t d - Limca" << endl; 
cout << "e - Mountain Dew \t f - Pepsi" << endl; 
cout << "g - 7-Up \t\t h - Maltina" << endl; 
cout << "i - Mirinda \t\t j - Malta Guiness \t" << endl; 
cout << "k - Malt \t\t l - Amstel Malta \t" << endl; 
cout << "m - maltina" << endl << endl;

cout << "Your order: ";

getline (cin, type);

while ((type != "a") || (type != "b") || (type != "c") || 
(type != "d") || (type != "e") || (type != "f") ||
 (type != "g") || (type != "h") || (type != "i") || 
(type != "j") || (type != "k") || (type != "l") ||
 (type != "m"))
{
    cout << endl;
    cout << "Invalid order! " << endl << endl;
    cout << "Choose from a - m only " << endl << endl;

    cout << "a - Coca-Cola \t\t b - Sprite" << endl; 
    cout << "c - Fanta \t\t d - Limca" << endl; 
    cout << "e - Mountain Dew \t f - Pepsi" << endl; 
    cout << "g - 7-Up \t\t h - Maltina" << endl; 
    cout << "i - Mirinda \t\t j - Malta Guiness \t" << endl; 
    cout << "k - Malt \t\t l - Amstel Malta \t" << endl; 
    cout << "m - maltina" << endl << endl;

    cout << "Your order again: ";

cin >> type; 

if ((type == "a") || (type == "b") || (type == "c") ||
 (type == "d") || (type == "e") || (type == "f") || 
(type == "g") || (type == "h") || (type == "i") || 
(type == "j") || (type == "k") || (type == "l") || 
(type == "m"))

{
 break; 
}

}



}
Last edited on
MatthewRock (481)
Your while loop condition is false. Use AND instead of OR.

If you input "a", first condition(type != "a") is false, but next(type != "b") is true. Change it.

Cheers!
Last edited on
xarmzon (5)
but if I use &&. the whole condition will become false. I used || since one of the condition must be true.
Last edited on
MatthewRock (481)
You can take whole condition from your if and negate it.
And you are right about the first part, my bad.
xarmzon (5)
thanks
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