need help~testing shift equivalent by using bool function

[cpluspluscpp]

 bool equivalent(int a[], int b[], int n){
	for(int i=0;i<n;++i){
	  for(int j=0;j<n;++j){
		if(a[(i+j)%n]==b[j]){
		 break; 
	}
	    else
		return false;
	}
	for(int shift=0;shift<n;++shift){
		  if(a[(i+shift)%n]==b[i])
		  return true;
		  return false;
	}
}
}

Hello, I am a beginner of c++. can anyone help me figure out this

problem? thank you! :) The code I wrote has some logical problem I guess. when I compile and run it, it does not show correct result.

Problem:
Write a function
bool equivalent(int a[], int b[], int n)
which takes two arrays a and b of length n and returns true if they are shift equivalent and false otherwise.
Definition: Let a and b be two integer arrays of the same length. We say that they are “shift equivalent” if array a can be right shifted to create array b.

[Smac89]

The reason your code is not working is because you are terminating the program early at line 8. Basically that nested for-loop will not work unless both arrays are the same i.e. contain the same data at the same positions.

This the same problem for the next for-loop, you are terminating early again.
Explain what you are trying to accomplish here with the code you have written then someone can help you figure something out

[cpluspluscpp]

hello, Smac89. thank you for your reply.
I am trying to create a Boolean function that determines whether two arrays,a and b, of length n are shift equivalent or not and returns true if they are shift equivalent and false otherwise.
ex: array a={1,2,3,4,5}
array b={3,4,5,1,2}
we can transform array a into array b by right shift each element of a to the “right” three places. So we can say that array a and array b are shift equivalent

[LendraDwi]

Well thanks to your post i'm having fun to find the answer :D

Try ths

x=-1
for i -> n
  if(a[0]=b[i])
    x=i
    break
If(x=-1) return 0
int j=x
for i -> n
  if(b[j]!=a[i])
     return 0
  j+=1
  If(j>=n) j=0
Return true