while loop conditions
I am having a hard time coming up with a solution on how to write my conditions for my while loop.
The while has to terminate when both x and y equals start_x and start_y.
So terminate when x = start_x and y = start_y..
the way i've done it now is by
while(x != start_x && y != start_y)
which terminates when one of the equals each other.. Any one with a solution??
The while has to terminate when both x and y equals start_x and start_y.
So terminate when x = start_x and y = start_y..
the way i've done it now is by
while(x != start_x && y != start_y)
which terminates when one of the equals each other.. Any one with a solution??
You decided that your condition should be
But you are using
| when x = start_x ... |
x != start_x . Why?
The while loop has too loop while
the x and y coordinates doesn't match start_x , start_y.
When i use this
while(x != start_x && y != start_y)
and lets say that start_x = 0, and start_y= 0
The while loop will terminate when x = 0 , and y = has some random value.
I want it to terminate when x=start_x and y = start_y.
the x and y coordinates doesn't match start_x , start_y.
When i use this
while(x != start_x && y != start_y)
and lets say that start_x = 0, and start_y= 0
The while loop will terminate when x = 0 , and y = has some random value.
I want it to terminate when x=start_x and y = start_y.
You say, you need to use equal (==) in your condition, but in your code you are using not equals (!=). Why did you place
!= in your code?
| terminate when they are equal... |
(x == start_x && y == start_y) →| run while they are not equal |
(not (x == start_x && y == start_y) )Applying DeMorgan laws, we get
(x != start_x || y != start_y)
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