printing chars with array.

[Endymion]

I just got done writing an array program, and now I got stuck on the next one I had to write. The code is supposed to display. My code displays the proper characters on each line, but it does decrease. I do not know why each new programming problem seems impossible.
<<<<<<<<
>>>>>>>>
<<<<<<
>>>>>>
<<<<
>>>>
<<
>>
The code seems to write a single character infinite loop

#include <iostream>
using namespace std;
int main()
{
	int i, j;
	char a = '<', b = '>';
	char print[2]{a, b};
	for (j = 0; j < 8; j++)
		{
			if (j % 2 == 0)
				print[j] = a;
			else
				 print[j]=b;
			for (i = 8; i > 2; i--)
			{
				cout << print[j]; 
			}
			cout << endl;
		}
		

	return 0;
}

[LendraDwi]

D you know how to print those lines without array ? Only using loop ?

[Endymion]

I believe so, but my assignment requires that I use an array. I have never done one with each line alternating, and with decreasing characters.

[LendraDwi]

I think you can create that loop, but instead of print it out, you can assign it to 2D array

[Endymion]

I have never attempted a 2d array before. I wrote this after a little internet research.
char print['<']['>'];
But I do not understand how to call the different elements of the array, or even if that is the right code.

[LendraDwi]

You can think that 2D or more as a diagram,
It'll looks like
char x[][]
The first [] fill wth how many sentence that you'll create
And the second one is how many character for each sentence

[Endymion]

So that means I will not include the characters < and > in the boxes? I just use the 2d for the placement of the characters?

[LendraDwi]

Yup, '<' or '>' wll assigned to the array its looks like x[0][0]='<' now the first character of the first sentence is <

[Endymion]

Okay after reading what you said here is my idea. I will create two arrays, one for each char. Then I will use each array in a separate loop to print their characters. I was thinking of using a modulus if else to determine which array is in play on which line. Does any of that sound correct?

[LendraDwi]

Yeh ts possible, but the reason why I ask you for create loop that can print those lines is for easier method to give the array an correct value

Like

char x[2][9];
for(int i=2;I>0;i++){
  for(int i=8;i>0;i++)
    if(i%2==0)x[i][j]='x';
    else x[i][j]='y';
}

Now x[0] is xxxxxxxx
And. x[1] is yyyyyyyy

[Endymion]

you wrote char X[2][9], what is the 9 for? Your code only displays 8 characters. Also is your inner loops supposed to use the variable j? If not how is j used in the code?

[LendraDwi]

Fist c String we'll need extra space for null character at the end of strng
And second ups my mistake ^^)a

[Endymion]

Okay, thanks a lot for taking the time to help me out. I am going to work on the code and post what I have in a few hours.

[Endymion]

Couldn't make anything that works, so I will try some more in the morning.