char* input

[Mor1994]

Hi everyone,

is there any way to get as an input a chars array, WITH spaces?
i have tried cin.getline, but it has problem with the enter keyboard.
for example, i want to get "A 6" as an input, and than to print it.
both of these doesnt work.
thanks !

 char s[3];
 1.cin>>s;
~~~~~~~~~~~
char *s=NULL;
 2.cin.getline(s,3);

[MiiNiPaa]

size of string "A 6" is 4 bytes. Also you are trying to get your line in null pointer.

constexpr size_t size = 128;
char buffer[size];
std::cin.getline(buffer, size);

[Mor1994]

is there another way to do that without size of bytes?
maybe char** or something?

[MiiNiPaa]

is there another way to do that without size of bytes?

Elaborate your question. You yourself tried almost this in your (2). I just made it use proper buffer.

[Mor1994]

i have an array *arr as a member data, and i want to insert names to it,
so when i want to get the input like "a b c d e", it only get a.
so im asking if there is any way to get these inputs with the spaces..

[MiiNiPaa]

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16

#include <iostream> struct foo { char* arr; foo() : arr(new char[16]) {} ~foo() { delete[] arr; } }; int main() { foo bar; std::cin.getline(bar.arr, 4); // If you need no more than 3 characters std::cout << bar.arr; }

a b c d e f a b

http://coliru.stacked-crooked.com/a/0496006b693383e3

[Mor1994]

thank you!