Help?

[2UX23TCk]

How can I input a number for example 54503 and let the program go through all the numbers and check if there is an even number or not? I think it should be inside a loop, and the condition for if it's even should be %2 == 0, but I don't know what the condition of the loop should be?

Sorry for bothering!

[Computergeek01]

First thing I would do is make sure that you take the input as a string. Then you would loop through the string based on it's length so:for(unsigned i = 0; i < Input.length(); ++i)//... and use "atoi()" or something similar with the element access operator to turn each character into an integer. Then you can do your modulous test on that for each element.

[2UX23TCk]

Is there any other way? Because the question tells me to input as an integer not a string.
Sorry for bothering again.

[ephraimr]

Yes, use this loop.

int n;
int m = n;
while(n > 0){
if( (n%10)%2 == 0) cout << "even digit!";
n/=10;
}

n%10 is the digit. It checks if digit is even, if it is even it outputs "even digit!". The loop goes through all the digits. Notice the n/=10; m is the unmodified original number. Please ask if you have more doubts.