Comparison

[GreenMan20]

I want to compare the memory address and pointer value of p, p + 1, q , and q + 1.
I want to understant what the following values actually mean. I can't quite wrap my head around whats going on.
When I run the code

I Get An Answer Of 00EFF680 for everytime I compare the adresss p with another pointer.
I Get An Answer of 00EFF670 for everytime I compare the address of q with another pointer

I Get An Answer of 15726208 when I look at the pointer value of p and I Get An Answer of 15726212 When I look at the pointer value of p + 1.

I Get An Answer of 15726192 when I look at the pointer value of q and I get An Answer of 15726200 Wehn I look at the pointer value of q + 1.

#include <iostream>
#include <string>
using namespace std;
int main()
{
        int val = 20;
	double valD = 20;
	int *p = &val;
	double *q;
	q = &valD;
	cout << "Memory Address" << endl;
	cout << p == p + 1;
	cout << endl;
	cout << q == q + 1;
	cout << endl;
	cout << p == q;
	cout << endl;
	cout << q == p;
	cout << endl;
	cout << p == q + 1;
	cout << endl;
	cout << q == p + 1;
	cout << endl;
	cout << "Now Compare Pointer Value" << endl;
	cout << (unsigned long)(p) << endl;
	cout << (unsigned long) (p + 1) << endl;
	cout << (unsigned long)(q) << endl;
	cout << (unsigned long) (q + 1) << endl;
	cout <<"--------" << endl;
        return 0;
}

[Bdanielz]

When you use == I do not think you are doing anything to the pointer.
Because == is just a comparison operator that returns true or false.
And then you are just printing one of the the pointers addresses with cout.

I think you need to use an assignment operator = instead.

[Serge1005]

I agree

[jlb]

What exactly are you trying to print with cout << p == p + 1;?

By the way the code in the first post shouldn't even compile because there are several errors, this is one of the lines that should cause an error.

[GreenMan20]

The Memory Address

[jlb]

If you want to print the memory address what is the purpose of the calculation? Why not just print the address? cout << p; Remember p is a pointer that is pointing to val, so printing p will print the address to print the value you need to de-reference the pointer:

cout << "The address of val is " << p << " and the value held in that address is: " << *p << endl;

[GreenMan20]

Wow so I was just over thinking it then? Then I can just compare the addresses and values in each pointer then right?
@jlb

[jlb]

Wow so I was just over thinking it then?

Probably.

Then I can just compare the addresses and values in each pointer then right?

Possibly. But I really don't know why you would want to compare the addresses.