Need help!
I am currently working on a code for a class I have and have been reading the text book and searching online for a way to get to the solution but so far nothing has made any sense. I need to make a code that can find the remainder of a very large number that is found from a .txt file. I understand the division behind the problem I just dont understand how to put it into code. If someone could give me a push in the right direction that would be amazing.
Problem:
Write program that computes the remainder of very long integer number that cannot be stored in C++ as in int type. You will get this long numbers from input data file and calculate the remainder when this number is divided by 97.
Sample Input:
1234567898765432
22222222222222222222222222222222
3333333333333333333333333333333333333333
3214282912345698765432161182
This is an outline for the code:
#include <cstdlib> //the standard C library header
#include
int main()
{
std::string si = "12";
int i = atoi(si.c_str()); //the c_str() function "converts"
}
//assume that dividend is 9 or more digits long
int main()
{
//variable declarations
int divider=97; //two digit number
int remainder;
string data; // input data
ifstream myIn; //input file
//open data file
myIn.open("longNumber.txt"); //input file name
//first data - priming read
myIn>>data;
while (myIn) //not end of file
{
cout<<" dividend is "<<data<<endl;
//process data -- this may be the focus
//calculate the remainder ( divided by divider)
//complete the code here
//
//
//remainder = ………………
cout<<" remainder is "<<<endl;
//next data to process
myIn>>data;
}
return 0;
}
Problem:
Write program that computes the remainder of very long integer number that cannot be stored in C++ as in int type. You will get this long numbers from input data file and calculate the remainder when this number is divided by 97.
Sample Input:
1234567898765432
22222222222222222222222222222222
3333333333333333333333333333333333333333
3214282912345698765432161182
This is an outline for the code:
#include <cstdlib> //the standard C library header
#include
int main()
{
std::string si = "12";
int i = atoi(si.c_str()); //the c_str() function "converts"
}
//assume that dividend is 9 or more digits long
int main()
{
//variable declarations
int divider=97; //two digit number
int remainder;
string data; // input data
ifstream myIn; //input file
//open data file
myIn.open("longNumber.txt"); //input file name
//first data - priming read
myIn>>data;
while (myIn) //not end of file
{
cout<<" dividend is "<<data<<endl;
//process data -- this may be the focus
//calculate the remainder ( divided by divider)
//complete the code here
//
//
//remainder = ………………
cout<<" remainder is "<<<endl;
//next data to process
myIn>>data;
}
return 0;
}
Thanks for the Help I actually found out the answer myself. I had to set a =0 for it to work fully. and then delete a couple cout statments
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