Merging Two Lists Together?

[aLee15]

I have to input two lists and then merge them together that lists them in numeric order. I must use this formula within the code:

void merge(const int list1[], int size1, const int list2[], int size2, int list3[])


This is all I have so far:

#include <iostream>
#include <list>
using namespace std;

void merge(const int list1[], int size1, const int list2[], int size2, int list3[]); // function prototype

const int SIZE = 80;
int list1[SIZE];
int list2[SIZE];
int list3[SIZE];

int main()
{

cout << "Enter list1: ";
cin >> list1[SIZE];

cout << "Enter list2: ";
cin >> list2[SIZE];

merge(list1, SIZE, list2, SIZE, list3); // invoking the function

return 0;
}

void merge(const int list1[], int size1, const int list2[], int size2, int list3[]) // doing the function
{


}


Also, I was testing a part of my code, and it only lets me input up to 2 numbers for my first list, and then I can't input anything for my second list.

Any help is much appreciated! Thank you!

[cire]

The first thing to realize is that you are only asking for 2 numeric inputs, so 2 numeric inputs is all you're going to get.

The second is that for an array (list1) of SIZE elements, valid indexes are 0 to SIZE-1. list1[SIZE] is not an element of list1, and using SIZE to index list1 is an error that results in undefined behavior.

[aLee15]

To solve the first issue, how do I ask for more inputs? The maximum list size is 80. Would I say list1[79] and list2[79]?

[cire]

To solve the first issue, how do I ask for more inputs?

By asking for input more than twice.

The maximum list size is 80. Would I say list1[79] and list2[79]?

Those would be the last elements in the array. You need to get input for each element of the array. Typically that would be done by looping SIZE times.