School assignment ("fibonacci numbers")

[VMZB]

Hello everyone! I am taking my first c++ class and we're on our last assigns of the semester. I have to write a program which repeatedly reads an integer between 1 and 1000, prints the following menu and reads the user's choice until the user chooses to quit, like so:

Enter an integer between 1 and 1000: 99
Choose one of the following:
1. Display all Fibonacci numbers up to 99
2. Display all prime numbers up to 99
3. Display all Fibonacci numbers that are also prime numbers up to 99
4. Display 5 randomly generated prime numbers between 1 and 1000
5. Quit.
Enter your choice:

I dont have the exact ideo on how to get through my choices 1 - 4!How to display the fibonaccis until number entered, prime numbers etc
this is what i got so far.....

#include <iostream>
#include <ctime>
using namespace std;
int main()

{
int integer, choice, fn;
int rn1 = 1 + rand() % 1000;

srand(unsigned(time(0)));

do
{
cout << "Enter an Integer between 1 and 1000: ";
cin >> integer;
cout << endl;

while(integer <= 1000)
{
cout << "Choose one of the following: "
<< endl
<< endl
<< "1. Display all Fibonacci numbers up to "
<< integer
<< endl
<< endl
<< "2. Display all prime numbers up to "
<< integer
<< endl
<< endl
<< "3. Display all Fibonacci numbers that are also prime numbers up to "
<< integer
<< endl
<< endl
<< "4. Display 5 randomly generated prime numbers between 1 and 1000 "
<< endl
<< endl
<< "5. Quit."
<< endl
<< endl
<< "Enter your choice: ";
cin >> choice;
cout << endl;
if(choice == 1)
{
for(fn = 1; fn < integer; fn ++)
cout << fn << endl;
break;
}
if(choice == 2)
{
for(fn = 1; fn < integer; fn ++)
cout << fn << endl;
break;
}
if(choice == 3)
{
for(fn = 1; fn < integer; fn ++)
cout << fn << endl;
break;
}
if(choice == 4)
{
for(rn1 = 1; rn1 < integer; rn1 ++)
cout << rn1 << endl;
break;
}
if(choice == 5)
{
cout << endl;
system("pause");
return 0;
}
while(choice < 0 || choice > 5)
{
if(choice < 0 || choice > 5)
{
cout << "Invalid entry! " << endl << endl;
}
break;
}
}
while(integer < 0 || integer > 1000)
{
if(integer < 0 || integer > 1000)
{
cout << "Invalid entry! " << endl << endl;
}
break;
}

}
while(integer <= 1000 || integer < 0 || integer > 1000 || choice < 0 || choice > 5);

system("pause");
return 0;
}


thanks for the help!!!

[xeyide]

Please use the code tags around your code, so it's easier to read.

Here are a few hints that I see.

- you'll need to #include <cstdlib> in order to use the srand psudo-random functions.

- A Fibonacci number is one that belongs to the Fibonacci's sequence: 0, 1, 1, 2, 3, 5, 8, 13...
http://en.wikipedia.org/wiki/Fibonacci_number
Right now your code prints out all integers up to the given number

- You don't need any break; statements in your if else statements, but this reminds me of the do-while-switch menu style that is so popular with homework assignments. Here is a sample of a simple do-while-switch menu code.

// [e-mail]

#include <iostream>
using namespace std;

int main( void ) {

   int choise;

   do { // does the block of code, before the check

      cout << "Simple Menu:" << endl;
      cout << "1. Hi!" << endl;
      cout << "2. Whatever. " << endl;
      cout << "3. Quit." << endl;;
      cout << "Please enter a choise : ";
      
      cin >> choise;

      switch ( choise ) {
         case 1: // if choise == 1
            cout << "Ok, I'm doing option #1! " << endl;
            // whatever block of code or function calls for option 1.
            break; // jumps to the end of the switch 

         case 2: // if choise == 2
            cout << "Ok, now I'm doing option #2! " << endl;
            // whatever block of code or function calls for option 2.
            break; // jump to the end of the switch

         case 3: // if chose == 3, the quit case.
            cout << "Thank you for using this menu. " << endl;
            break; // jump to the end of the switch

         default: // input doesn't match any case.  
            cout << "Wrong Option! " << endl;

       } // switch's end.
   } while ( choise != 3 ); // read as "Keep doing everything between my { } 
                            // while "choise" is not equal to 3." 
   return 0;
}

[kamyarseifi]

for the fibonacci numbers you can do as below:

void fibo(int m)
{
int m,a1,a2,i=2;

if(m<2) {
pirntf("the a1=1 and a2=1 in fibonacci");
 i=m+1;// to not to enter in loop
}

num[0]=1; num[1]=1;

for(;i<m;i++) //if i !=m+1 the loop will start
{ 
  a1=1;a2=1;a3=a1+a2;
 printf("%d",a3);
  a1=a2;a2=a3;
 } 
}

then in your option1 place function fibo() or if you shouldn't use function place it normally

int m,a1,a2,i=2;

scanf("%d",&m);//the m is 99 here!

if(m<2) {
pirntf("the a1=1 and a2=1 in fibonacci");
 i=m+1;// to not to enter in loop
}

num[0]=1; num[1]=1;

for(;i<m;i++) //if i !=m+1 the loop will start
{ 
  a1=1;a2=1;a3=a1+a2;
 printf("%d",a3);
  a1=a2;a2=a3;

[VMZB]

Thanks 4 the response! I tried it without the "break;" statemts in my "if" stmnts but it takes me back to the "Enter your choice:" option... About the fibonacci nums i'm still a bit confused, if my "integer" variable entered is 99 for example, how do i get the fibo nums to that number?
Then i'll have to get the primes to that same num as well!

Thanks much!!!