pointers and arrays questions

[JethroA7]

I'm wondering how I can calculate the average but instead of calculating all the numbers in the array, the first one is dropped. Then the second and so fourth.

#include <iostream>
#include <iomanip>

using namespace std;


void sort(double* score, int);
double average(double* score, int);


int main()
{
	int numTestScores;   
	double *testScorePtr; 
	double testAverage;   

						  
	cout << "\n\tHow many test scores will you enter? ";
	cin >> numTestScores;

	
	while (numTestScores < 0)
	{
		cout << "\n\tThe number cannot be negative.\n";
		cout << "\tEnter another number: ";
		cin >> numTestScores;
	}

	
	testScorePtr =  new double[numTestScores];

	
	for (int count = 0; count < numTestScores; count++)
	{
		cout << "\n\tEnter The test score for test # " << (count + 1) 
			<< ": ";
		cin >> testScorePtr[count];

		while (testScorePtr[count] < 0)
		{
			cout << "\n\tThe number cannot be negative.\n";
			cout << "\tEnter another number: \n";
			cin >> numTestScores;
		}
	}


	
	sort(testScorePtr, numTestScores);


	
	testAverage = average(testScorePtr, numTestScores);

	
	cout << "\tThe average of all tests: " << testAverage;



	return 0;
}


void sort(double* score, int size)
{
	int startScan, minIndex;
	double minValue;

	for (startScan = 0; startScan < (size - 1); startScan++)
	{
		minIndex = startScan;
		minValue = *(score + startScan);

		for (int index = startScan + 1; index < size; index++)
		{
			if (*(score + index) < minValue)
			{
				minValue = *(score + index);
				minIndex = index;
			}
		}

		*(score + minIndex) = *(score + startScan);
		*(score + startScan) = minValue;
		
	}
}



double average(double *score, int size)
{

	double total = 0.00;
	double totalAverage;
	int index = 0;

	cout << fixed << showpoint << setprecision(2);

	for (int count = 0; count < size; count++)
	{
		
		total += *score;
		score++;

		

	}
 
	totalAverage = total  / size;

	return totalAverage;
}

[Thomas1965]

One way is to pass the second elem of your array to the average function, then the third , fourth....