Vector using structure datatype

[yup2]

Im having an extremely hard time finding a solution to this, I've looked on youtube and google but have not found a solution. With the followign code I have been unable to do the following:

1. Add information to a vector using the person datatype.
2. Creating a new element within the vector (pushback) once the information has been entered.

Thanks in advanced for your help.

  #include <iostream>
#include <vector>
#include <string>
#include <vector>

using namespace std;

struct person
{
    string firstname;
    string lastname;
    string email;
    string id;

};


int main()
{
    vector<person> p;


    cout << "First name: ";
   cin >> p.firstname;
   cout << "\n";
   cout << "Last Name: ";
    cin >> p.lastname;
     cout << "\n";
    cout << "Email: ";
    cin >> p.email;
     cout << "\n";
    cout << "ID: ";
    cin >> p.id;
     cout << "\n";
    p.push_back({p});


    for (int i =0; i < 5; i++)
    {
        cout << p[i] << endl;
    }

}

The error I am getting is std::vector<person> has no member named 'firstname', 'lastname' and so on.

[H00G0]

Hello yup2

line 20 vector<person> p;
you're defining and empty vector, it equates to an empty array, you have to push back a member into the vector before you can call it.

You can never use p.firstname you have to specify which member of the vector you're referring to with []

in your case you could do that:

#include <iostream>
#include <vector>
#include <string>
#include <vector>

using namespace std;

struct person
{
    string firstname;
    string lastname;
    string email;
    string id;

};


int main()
{
    vector<person> p;

//hold temporary data to push back to p vector
    person tempPerson;

    cout << "First name: ";
    cin >> tempPerson.firstname;
    cout << "Last Name: ";
    cin >> tempPerson.lastname;
    cout << "Email: ";
    cin >> tempPerson.email;
    cout << "ID: ";
    cin >> tempPerson.id;
    
    p.push_back(tempPerson);


    for (int i =0; i < p.size(); i++)
    {
       cout << "\n\nFirst name: " << p[i].firstname
       << "\nLast name: " << p[i].lastname
       << "\nEmail: " << p[i].email
       << "\nID: " << p[i].id;
    }
}

Note that line 40 cout << p[i] << endl; p doesn't have an overloaded operator <<, so if you want you can either make a function to do so in the struct or like I did, display each of the variable one after the other.

Hope this helps

EDIT: also, line 38: for (int i =0; i < 5; i++), this is going to crash your program if your vector doesn't have at least 5 members, which in your case doesn't. You can use .size() for vectors to return the size of the vector, therefore not attempting to access data that isn't allocated

[yup2]

Thanks a ton, you just cleared up a concept that I was looking into for hours. It work's perfectly.

[H00G0]

My pleasure! glad to have helped!