How do i make cout depend on cin

[jjimijimmy]

I'm a beginner at c++ programming, and i cant figure out how to change what cout is, depending on what the user of the program inputs. My program asks a yes or no question, and if the user inputs <const char string[80] = ("yes")> cout will say something different as opposed to if the user inputs <const char string[80] = ("no")>

[joatmon]

a

[D80DSL3A]

jjimijimmy wrote:

...i cant figure out how to...

Advice: Don't try to "figure out" how to do this stuff. Study how to do it. Read books or online tutorials. This will save you much pain.

[S6k9GNh0]

joatmon, really...

jjimijimmy, http://social.msdn.microsoft.com/forums/en-US/vclanguage/thread/9f3b9646-5b2d-4ff0-88c8-bf72e56f12cd/

[Duthomhas]

I think the OP is simply looking for some flow control.

Read the tutorials on this site and you will understand something like this:

#include <iostream>
using namespace std;

int main()
  {
  cout << "Would you like some advice ('y' or 'n')? ";
  char c;
  cin >> c;
  cin.ignore( 500, '\n' );
  if (c == 'y')
    {
    cout << "Look before you leap.\n";
    }
  else
    {
    cout << "OK then. No advice for you!\n";
    }
  cout << "Have a nice day!\n";
  return 0;
  }

Hope this helps.

[NewBeeBP]

I am still new at this and it took me a few days to figure out how to make a conversion for coins. The cout is based on cin. Hope it helps.

#include <iostream>
using std::cout; // program uses cout
using std::cin; // proram uses cin
using std::endl; // program uses endl


int main() // function main begins program execution
{
	float money; // creates integer for money input
	int PENNY = 1; //creates integer for penny
        int DIME = 10; // creates integer for dime
	int QUARTER = 25; // creates integer for quarter
	int NICKEL = 5; // creates integer for nickel
	int total = 0; // creates integer for total and initializes it
	int choice = 0; // creates integer for choice and initializes it

	cout << "Please enter in a dollar amount to convert it to change\n"; //prompts user 
	>> cin >> money; // user enters dollar amount
	cout << endl; //end prompt
		
	cout << "To determine how many pennies, dimes, quarters or nickels, enter\n"; //display message
	cout << "MENU\n"
       << "1) PENNY\n" //user inputs 1 for penny conversion
       << "2) DIME\n" //user inputs 2 for dime conversion
       << "3) QUARTER\n" //user inputs 3 for quarter conversion
       << "4) NICKEL" << endl; //user inputs 4 for nickel conversion
	cin >> choice; //user enters number corresponding to coin
	cout << endl; //end prompt
	{
	if ( money <= 1 ) // if money input is 1 or less
	 return -1; // end program
		}
	{ // begin if...else
		if ( choice == 1 ) //if user chooses 1 for penny then
		 total = (int)( money * 100 ) / PENNY; // multiply money times 100 divided by 1 to get pennies
           else  
		     if ( choice == 2 ) //if user chooses 2 for dime then
              total = (int)( money * 100 ) / DIME; // multiply money times 100 divide by 10 to get dimes 
                else 
			     if ( choice == 3 ) //if user chooses 3 for quarter then
	               total = (int)( money * 100 ) / QUARTER; //multiply money times 100 divide by 25 for quarters
	                 else  
				       if ( choice == 4 ) //if user chooses 4 for nickel
	                     total = (int)( money * 100 ) / NICKEL; //multiply money times 100 divide by 5 for nickels
             
		
	if ( choice == 1 ) //if user choice was 1 display conversion and message
		cout << "The result is: " << total << " PENNIES in " << "$" << money << endl; // display message with amount of coins and money input
	else 
	if ( choice == 2 ) //if user choice was 2 display conversion and message
		cout << "The result is: " << total << " DIMES in " << "$" << money << endl; // display message with amount of coins and money input
	else 
	if (choice == 3 ) //if user choice was 3 display conversion and message
		cout << "The result is: " << total << " QUARTERS in " << "$" << money << endl; // display message with amount of coins and money input
	else 
	if ( choice == 4 ) //if user choice was 4 display conversion and message
		cout << "The result is: " << total << " NICKELS in " << "$" << money << endl; // display message with amount of coins and money input
} // end if..else

system("pause"); // keep window open
return 0; // indicates successful termination
}

[NewBeeBP]

I worked on your question today to help you and teach myself. So this is what I came up with.

#include <iostream> 
using namespace std; // uses std namespace

int main() // function main begins program execution
{  
	char choice = 0; // creates character for choice
	char y = 0; // creates character for y
	char n = 0; // creates character for n
	
	  
		cout << "Would you like some advice?\n"; // display question to user
		cout << "Y for yes and N for no\n"; // prompts user for a Y or N
		cin >> choice; // user enters in letter
	
  		
  switch ( choice ) // switch statement to determine what input letter and what to display based on input
  {
	case 'y': // lower case choice for y
	case 'Y': // upper case choice for Y
		cout << "\nLook before you leap.\n"; // message displayed if user inputs Y or y
		break; // exit switch
	case 'n': // lower case choice for n
	case 'N': // upper case choice for N
		cout << "OK then. No advice for you!\n";  // message displayed if user inputs N or n
		break; //exit switch
	default: // call all other characters
	    if ( choice != y || n ) // if the choice is not a y or n display below message
	cout << "Sorry only Y or N is allowed.\n"; //message displayed if condition is not met
	cout << endl; //output a newline

  } // end switch   
	  cout << "Have a nice day!\n"; //display message outputted with each choice
  cout << endl; //output a newline
 
system("pause"); // keeps window open, best used for learning codes, poses security vulnerability
  return 0; // indicate successful termination
  } // end function main 

[edithsong]

You can negate the need for 'y' and 'Y' by using:
switch (tolower(choice))

Or:

if (tolower(choice) == 'y')
stuff
if (tolower(choice) == 'n')
stuff
else
stuff

A few less lines of code but either way is good.

instead of system pause its usually better to simply have a

cout << "Pause:\n" << "Enter to exit";
cin << new e;
delete e;
return 0;

Or the like.
:)