Function name as parameter?

[CheesyBeefy]

I want to do something like this, but I don't know how:

// +------------------------------------+
// | Brad Summers, (c) Contrast Gaming	|
// | testcode2.cpp                      |
// | Testing Things (Code)              |
// +------------------------------------+

#include <iostream>
using namespace std;

void myOtherFunction() {
        cout << endl << "And this is the result.";
}

void myFunction(function otherFunction, char parameter[80]) {
	cout << parameter;
	otherFunction();
}

int main() {
	myFunction(myOtherFunction, "I am calling a function with a function.");		
	cin.ignore(80,'\n');
	return 0;
}

Is this possible?

[helios]

Following your example,

#include <iostream>
using namespace std;

void myOtherFunction() {
        cout << endl << "And this is the result.";
}

void myFunction(void (*otherFunction)(), char parameter[80]) {
	cout << parameter;
	(*otherFunction)();
}

int main() {
	myFunction(&myOtherFunction, "I am calling a function with a function.");		
	cin.ignore(80,'\n');
	return 0;
}

[CheesyBeefy]

Works great, but so I can understand it, what do the * and & symbols mean in C++?

[helios]

void (*otherFunction)()
This means "a pointer called 'otherFunction', to a function that takes no parameters and returns nothing".

&myOtherFunction
This means "the memory address of the function 'myOtherFunction'".

(*otherFunction)();
This means "dereference the pointer 'otherFunction' and call the function it points to".