Code problem

[EGoodman]

Can't get it to go past the selection process. if I make a choice it does not even display the corresponding code for that selection.

[long double main]

Because of your infinite loop here:

while(choice == 'a')
    while (counter <= limit)
        ;

Anyways, what I was trying to get at was something like:

if (choice == 'a')
{
    // Do stuff
}
else if (choice == 'b')
{
    // Do other stuff
}
else if (choice == 'c')
{
    // You get the point
}

You could technically use a switch statement for something like that, but I don't know if you know how to use those yet....

[EGoodman]

i kind of do just could get that to work either

[EGoodman]

still won't let me past the menu for any selection.

[EGoodman]

ok got the other selection to somewhat work but the limit variable will not change to the new input or does any of the other variables.

[long double main]

Okay, let me give you a hint.

if (choice == 'a')
{
    // Ask user how many numbers
    while (counter < limit) // I would use a for loop, but this works too
    {
        // Get the numbers
        ++counter;
    }
    // Print highest number
}
else if (choice == 'b')
{
    // And so on and so forth
}

[EGoodman]

program still stops cold after trying to set the limit variable wont even ask for the numbers to try an get to the limit. I am lost here and the b option will only allow a single number to be entered and returns a not entered number for the output on it. The only option that works correctly is c the exit option. I need this to compare a series of numbers also and it doesn't do that. It also will not change the variables to the input variables.

[long double main]

What do you have so far?

EDIT: Let me guess...

while (counter <= limit); // Should not be a semicolon here
{
    // ...
}

[EGoodman]

Took that completely out of the current program. so I could advance and see what it would do, even though it is supposed to be how the supposed loop is to be ended and return the user to the menu.

[EGoodman]

Current code

#include <iostream>
#include <cctype>
using namespace std;

int main()
//set variables
{	
	int highnum(0);
	int lownum(100);
	int limit(0);
	char choice; 
	int counter(0);
	int num;
	
	
		cout<<   "A - Find the largest number with a known quantity of numbers. ";
		cout<<   endl;
		cout<<	 "B - Find the smallest number with an unknown quantity of numbers. ";
		cout<<   endl;
		cout<<	 "C - Quit";
		cout<<	 endl;
		cout<<	"Enter your choice. ";
		cin>>  choice;
		cout<<	endl;
	

		
	if(choice=='a')
	{
		 cout << " How many numbers would you like to compare? ";
		 cin >> limit;
		 
		 ++ counter;
		 cout << endl;
		 cout<< "Enter your number ";
		 cin >> num;
		 
	
		
	if (num > highnum)
		cout << "your highest number was ";
		 cout << highnum << endl; 
	}
	if  (choice == 'b')
	{
		cout << "Enter your numbers. ";
		cin >> num;
		cout<< "Your lowest number was ";
		cout << lownum << endl;
	}
		
	if (choice == 'c')
		cout << "thank you for playing. " << endl;
		
	cin.get();
	cin.get();

	return (0);
}

[long double main]

Let me show you where the loop goes for choice A.
Afterwards, see if you can figure out how to do choice B.

if (choice=='a')
{
    cout << " How many numbers would you like to compare? ";
    cin >> limit;
        
    //while (counter < limit) { // Do not put a semicolon after the while!
    ++ counter;
    cout << endl;
    cout<< "Enter your number ";
    cin >> num;
    // If num is bigger than current highest number (highnum)
    // then set the highest number to num
    //}

    if (num > highnum) // Get rid of this line
    cout << "your highest number was ";
    cout << highnum << endl;
}

[EGoodman]

ok that works. now to actually get it to loop the num entry process and figure out how to stop the b option when I get it to actual y loop.