Printing an Array after passing it to a function

[kichithewolf]

I'm trying to pass an array from a function to another to print it, but the numbers are not displaying properly.

#include <iostream>

using namespace std;

int Input(int One[2][3])
{
     for(int row = 0; row < 3; row++)
     {
             for(int column = 0; column < 4; column++)
             {
                     cout << "Input element [" << row << "][" << column << "]: ";
                     cin >> One[row][column];
             }
     }     
}

int Print(int One[2][3])
{
     for(int row = 0; row < 3; row++)
     {
             for(int column = 0; column < 4; column++)
             {
                     cout << One[row][column] << " ";
             }
             cout << endl;
     }
}





int main()
{
    int One[2][3];
    
    Input(One);
    Print(One);
    
    cin.get();
    cin.ignore();
    return 0;
}

However when entering 1, 2, 3, ..., I get this as output:

1 2 3 5
5 6 7 9
9 10 11 12

The number 5 is repeated and so is 9.

[vlad from moscow]

The loops shall be set the following way

     for(int row = 0; row < 2; row++)
     {
             for(int column = 0; column < 3; column++)
             {
                    // some code
             }
     } 

Also the both function shall have return type void because they return nothing.

[kichithewolf]

Changing the code works, but it only produces 2 rows and 3 columns. I'm trying to have 3 rows and 4 columns.
What I get:

1 2 3
4 5 6

What I want:

1 2 3 4
5 6 7 8
9 10 11 12

[expor]

That's because your int array One is initialized with [2][3]. So you have two rows and two columns. That means you have to change it to [3][4] to get what you want.

[kichithewolf]

Oh that works! Thanks for all the help!