explination

[KoronaKyle]

int n=12;
cout<< n++<<endl;//12
cout<< ++n<<endl;//14
cout<< n+++1<<endl;//15
cout<< ++n+1<<endl;//17
cout<< n+1<<endl;//17
cout<< n<<endl;//16

i have a questin since n 12 n++ must be 13? why is this value not displayed instead it is 12 in the first cout?

[zb0S216C]

The post-fix increment/decrement operator returns a copy of its operand before increment/decrementing it. This behaviour is equivalent to this:

int n(12);
std::cout << n;
n += 1;

The pre-fix increment/decrement operators increments/decrements the value of its operand, then returns the new value.

_Wazzak

[KoronaKyle]

can you please explain till the first 17? how do we get there...this is getting more clear for me but still i need to know the logic.

[gtkano]

n++ n increments after instruction was made
++n n increments before instruction


using n++ && ++n

int n=12;
cout<< n++<<endl;//12
cout<< ++n<<endl;//14
cout<< n+++1<<endl;//15
cout<< ++n+1<<endl;//17
cout<< n+1<<endl;//17
cout<< n<<endl;//16 

without n++ && ++n

int n=12;
cout<< n<<endl;//12
n+=1;  //n=13

n+=1; //n=14
cout<< n<<endl;//14

cout<< n +1<<endl;//15
n+=1 ; //n=15

n+=1 ; //n=16
cout<< n +1<<endl;//17

cout<< n+1<<endl;//17

cout<< n<<endl;//16 

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