Why do I have to hit ENTER twice here?

[enosmac]

I have some code that is giving me fits. I need to check that the data entered by the user is an integer between 0 and 10. This code is broken because the user has to enter their number twice (hitting enter after each input). It does work that it catches non-integers or numbers less than 0 or greater than 10, but you still have to enter the number twice. How can I fix this code so I only have to enter the number once?

case 2:	{
	char blank;
	int value;
	cout << "Using overloaded constructor" << endl << endl;
	cout << "Choose a integer 0-10 for Matrix Row and Column Size." << endl;
	cin >> value;

//if I remove the while below, it works fine.  I have tried removing
//the cin.clear and cin.ignore to no effect

	while ( !(cin >> value) || value < 0 || value > 10){
		
	cout << "       PLEASE SELECT YOUR MATRIX SIZE, 0-10: ";
	cin.clear();
	cin.ignore (1000, '\n');
				}
	Matrix neo(value);
	cout << "Matrix Created with overloaded constructor." << endl;
	cout << "Displaying Matrix using overloaded << operator." << endl;
	cout << neo;
	cout << endl << endl;
	cout << "Press ENTER to continue." << endl;
	cin.get(blank);
	cin.get(blank);
			
	}
	break;

Can anyone suggest a better way to check for integer values being inputted rather than the while statement?
Thanks a TON.

[ryancb06]

Your running CIN twice.

cout << "Choose a integer 0-10 for Matrix Row and Column Size." << endl;
cin >> value;

while ( !(cin >> value) || value < 0 || value > 10){

[enosmac]

Ah, thanks a lot. Issue resolved :)