One integer instead of two

[dice980]

How can I change it so that I input only one integer instead of two?

#include <iostream>
using namespace std;


int main()
{ 
int n;
int y; 
int i; 
int prime; 


cout <<"Enter two integers : ";
cin >> n >> y;

while (y >= n) 
{ 
prime=0;

cout << "\n" << n << ":\t" ;

for(i=2;i<n;i++)
if(n%i==0)
{ 
cout << i;
prime=1;
}
if(prime==0)
cout <<"Prime";
n++;
}


cout << "\n";
system ("pause");
return 0;
} 

[KungFu97]

cin >> n;

I think that's what you mean anyway.

[dice980]

Oh okay thank you i did that but i never deleted the while (y >= n) now it works thank you.

[KungFu97]

No problem, happy to help!

[dice980]

One more thing I have a code that lists if the number is a prime number or a perfect number i want to incorporate the other one where it lists the divisors how would i do that?

#include <iostream>
#include <string>
using namespace std;

int checkprime(int n)
{
	int i;
	int prime=1;
	for(i=2;i<n/2;i++)
	{
	if(n%i==0)
		{
		prime=0;
		break;
		}
	}
	return prime;
}
	
int isperfect(int x)
{
	int sum=0;
	int i;
	for(i=1;i<x;i++)
	{
		if(x%i==0)
		{
			sum=sum+i;
		}
	}
	
	if(sum==x)
	{
	return 1;
	}
	else
		{
		return 0;
		}
}

	
int main()
{
	string input;
	do

{
	int b;
	cout << "*******************************" <<endl;
	cout << "Enter number: ";
	cin >> b;
	cout << "*******************************" <<endl;


	if(isperfect(b)==1)
	{
	cout<<b<<" is a perfect number. \n";
	}
	
	else
	{
	cout << b << " is not a perfect number. \n";
	}
	
	
	
	if(checkprime(b)==1)
	{
	cout << b << " is a prime number. \n";
	}
	
	else
	{
	cout << b << " is not a prime number. \n";
	}

	cout <<"*******************************" <<endl;
	cout << "Do you want to quit?" << endl 
		<< "[Y]es [N]o: " ;
	cin >> input;
}	while ((input == "N") || (input == "n")); 

	return 0;
}

[KungFu97]

#include <cmath>
#include <iostream>
using namespace std;
int main()
{
	int num, countA, countB;
	
	cout << "Please enter a positive maxiumum integer value you wish to find divisors: \n";
	cin >> num;
	if (num <= 0)
	{
		cout << "The input entered was invalid. Please input a positive whole integer.\n";
	}
	else
	{
	
		for(countA = 1; countA <= num; countA++)
		{
		
			cout << "Divisors of " << countA << ": ";
			for(countB = 1; countB<= num; countB++)
			{ 
				if(countA % countB == 0)
				{			
					cout << countB << " " ;
				}			
			}
			cout << endl;
		}
	}
	return 0;
}

This is a short example of how you could do something like that.

[dice980]

How can I make it so that after inputting an integer not within the range, you have the option to quit or to continue? I have it set like that if you do enter an integer within the range but can't figure out how to have it setup the same.

#include <iostream>
#include <string>
using namespace std;


int checkprime(int n)
{
	int i;
	int prime=1;
	for(i=2;i<n/2;i++)
	{
	if(n%i==0)
		{
		prime=0;
		break;
		}
	}
	return prime;
}
	
int isperfect(int x)
{
	int sum=0;
	int i;
	for(i=1;i<x;i++)
	{
		if(x%i==0)
		{
			sum=sum+i;
		}
	}
	
	if(sum==x)
	{
	return 1;
	}
	else
		{
		return 0;
		}
}


	
int main()
{
	
	
	string input;
	do

{
	int b;
	int i;
	int prime=1;
	cout << "*******************************" <<endl;
	cout << "Enter number: ";
	cin >> b;
	cout << "*******************************" <<endl;






	if (b<0|| b>1000)
	 
			
				{
				cout << "Please enter an integer that is within the range." <<endl;
				system ("pause");
				break;
				}
	





		if(isperfect(b)==1)
	{
	cout<<b<<" is a perfect number. \n";
	}
	
	else
	{
	cout << b << " is not a perfect number. \n";
	}
	
	
	
		if(checkprime(b)==1)
	{
	cout << b << " is a prime number. \n";
	}
	
	else
	{
	cout << b << " is not a prime number. \n";
	}
											

	{ 
		prime=0;
		cout << "Divisors of "<< b << ":" << " ";

		for(i=2;i<b;i++)
		if(b%i==0)
	{ 
		cout << i << " ";
		prime=1;
	}
		b++;
	}
	
	cout <<"\n*******************************" <<endl;
	cout << "Do you want to quit?" << endl 
		<< "[Y]es [N]o: " ;
	cin >> input;
}	while ((input == "N") || (input == "n")); 

	return 0;
}