spaces in char array input

[crinkelite]

Hi folks I'm relatively new to this and I'm sorry for posting such a mundane question but I'm writing a VERY simple program to practice the things I've learned so far in the tutorial section,
I think its best to post all the code :

------------------------------------------------------------------------
#include <iostream>
using namespace std;

int perimiter (int x, int y){
return ((x+x)+(y+y));}

int area (int x, int y){
return (x*y);
}

int main()


{
int height;
int width;
char name [30];
cout << "please enter your full name : ";
cin >> name;
cout << "hello " << name << endl;

cout << "Enter the height of your rectangle : ";
cin >> height;
cout <<"\n";
cout << "Enter the width of the rectangle : ";
cin >> width;

int choice;
cout << "enter 1 for the area or 2 for the perimeter (or 3 to exit) : ";
cin >> choice;
if (choice == 1){
goto AREA;}
else if (choice == 2){goto PERIMETER;}
else goto end;
PERIMETER:
cout << "the perimeter is : "<< perimiter (height, width) << "\n";
goto end;

AREA:
cout << "the area is : " << area (height, width)<< "\n";
end:
system ("pause");

return 0;
}


------------------------------------------------------------------------

the problem is that whenever I enter a name with a space it skips all other inputs and just prints all the outputs and ends the program, this does not happen if I use a name with no spaces

I am using Bloodshed Dev-C++ in windows xp 32

I hope I have made myself clear enough, thanks in advence

ps, I cant seem to get the code /code tags to work so sorry bout the messy post.

[eker676]

Make name a char* or a string and use cin.getline(char* name) or getline(cin, string)

Be aware of mixing getline and cin though. There are many side effects.

[hannad]

@ Your Code tags.. Use

[ code]
Your code
[ /code]

Or the Hash sign next to the reply text box.

==EDIT==

eker676 has answered you :P.

[crinkelite]

thanks eker676 for the reply, I better go back to the tutorial pages and re read,

cheers hannad, I was using the higher case CODE,

[crinkelite]

I thaught the best aproach ( meaning the only one I'm half way familiar with) would be to create a pointer (char * p1) and point it at the char array

int height; 
    int width; 
    
    char name [30];
    char * p1;
    
    p1 = &name;
    
    cout << "please enter your full name : "; 
    cin >> *p1;
   
    cout << "hello " << name << endl;

however it will not compile.
i get an error saying:

cannot convert 'char (*)[30]' to 'char*' in assignment.

I dont know what I am doing wrong in this case. I realise that there is probably an easier way to do this but I am trying to get to grips with character arrays and It's bugging the hell out of me.

thanks for reading.

[chungolongo]

You cannot use plain "cin" as it stops reading when encountering whitespace.

One solution is:

char name [30];
cout << "please enter your full name : ";
cin.getline( name,29);
cout << "hello " << name << endl;

An array of chars is a string (old type).

Here:
You declare an array of chars - holds 30 chars.
Using cin.getline - You read the entire line entered including whitespace.
(name, 29) = "name" is where you want the chars stored and "29" is the maximum number allowed to be read.

You might say -"Hey, I said 30!". True, but this type of string needs a terminating ' 0' to say where the it stops. Thus 29 is the maximum number.

[jsmith]

Your compile error is because name, when used by itself, is already a char*. &name is therefore a pointer-to-a-char*, or a char**.

Syntactically correct would have been p1 = name, but semantically the code still wouldn't work (see previous reply).

[crinkelite]

thank you very much for clearing that up for me, you've all been extreemly helpul