| Natalyias77 (10) | |
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I am writing a program for school.The details are that it only prints the even numbers between 2 numbers that have been entered from the keyboard. It must include a loop and call a function: print_even. I can get it to run but on the return value from my function, it is also returning the value... What I mean is my return statement is: "return -1;". It returns the numbers to be printed but also the '-1'. If I put a 0 or 1, it will return that. I understand its doing what I tell it to, but I only want the numbers. So my output is this: Select the start number: 2 Select the end number: 10 The even numbers between 2 and 10 are 4 6 8 -1 Press any key to continue . . . Below is my code. Any suggestions? Please and Thank you! int print_even(int a, int b); int main() { int startNumber = 0; int endNumber = 0; cout << "Select the start number: "; cin >> startNumber; cout << "Select the end number: "; cin >> endNumber; if (endNumber < startNumber) { cout << "End number is less than start number. Please try again"<< endl; } cout << "The even numbers between " << startNumber << " and " << endNumber << " are " << print_even(startNumber, endNumber) << endl; system ("pause"); return 0; } int print_even(int a, int b) { for(int i=a+1;i<b;i++) { if(i%2!=0) continue; cout<<i<<endl; } return -1; } | |
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| Jamil Shehzad (6) | |
| make datatype of ur print_even function as void. coz i dont think so that u need return; statement........... hope it will work also remove return -1; | |
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