code please

[dipen45]

Please give the c++ code for following problems.

1) Write a C++ program to calculate x raised to the y power. The program should have a while repetition control structure.solved

2) Print the integers form 1 to 20 using a while loop and the counter variable x. Assume that the variable x has been declared, but not initialized. Print only 5 integers per line. Hint: Use the calculation x%5. When the value of this is 0, print a newline character, otherwise print a tab character.

[masterofpuppets690]

I'll help you write that if you'd like but I'm not doing your assignment for you because that won't help you at all. Make a stab at the code, post it here and we'll dutifully give you help but you get nowhere in life just asking for it to be done for you.

[Volatile Pulse]

Just because I'm an ass. Here is your code:

// Number 1
#include <iostream>
#include <cmath>

int main() {
   int x, y;
   std::cout << "Enter X: "; std::cin >> x;
   std::cout << "Enter Y: "; std::cin >> y;
   while (true)
      std::cout << "X^Y = " << pow(x,y) << "\n";
   return 0;
}

// Number 2
#include <iostream>

int main() {
   while (true)
      std::cout << "12345\n678910\n1112131415\n1617181920\n";
   return 0;
}

[dipen45]

@ volatile tx, but your both program gives continuous loop...

finally I got the answer which work perfectly.

#include <iostream>
using namespace std;

int main()
{
	int x, y, i, power;

	i = 1;
	power = 1;

	cout << "Enter x: ";
	cin >> x;
	cout << "Enter y: ";
	cin >> y;

	while ( i <= y ) {             // to multiply the x itself to the no. of y
		power = power * x;
		i++;
	}

	cout << "x to the power y is: " << power << endl;
	return 0;
}

looking for 2nd answer.

[masterofpuppets690]

Oh fine I'll give you the second answer because I'm a loverly person :P

#include <iostream>

using namespace std;

int main()
{
    int x = 0;
    while(x <= 20)
    {
        if(x % 5 == 0 && x != 0)
        {
            cout << " " << x << endl;
        }
        else if((x % 5 == 1 || x == 0) && x != 1)
        {
            cout << x;
        }
        else
        {
            cout << " " << x;
        }
        x++;
    }
}

[dipen45]

tx master, here I got the simple code..

#include <iostream>

using namespace std;

int main()
{
	int x;
	x = 1;

	while ( x <= 20 ) {
		cout << x;

		if ( x % 5 == 0 )
			cout << "\n";
		else
			cout << "\t";
		
		x++;
	}
	
	return 0;
}