longest sentence, need help

[TFFBRAIN]

#include "stdafx.h"
#include <stdio.h>
#include <conio.h>
#include <string.h>
void main()
{
int x=0,y=0,max=0;
char st[100];
char at[]="this is the end";
printf ("\n give me a setence:");
fflush(stdin);
gets(st);
for (int i=0;i<100;i++)
{
if ((st[i]!=' ')&&(st[i+1]==' '))
x++;
if (st[i]=='\0')
break;
}
x++;
max=x;
do
{
printf ("\n give me a sentence:");
fflush (stdin);
gets(st);
if (st[0]!=' ')
y++;
for (int i=0;i<100;i++)
{
if ((st[i]!=' ')&&(st[i+1]==' '))
y++;
if (st[i]=='\0')
break;
}
if (y>x)
max=y;
else
max=x;
y=0;
}while (strcmp(st, at)!=0);
printf ("\n the number of words is %d",max);
getch();
}

[vlad from moscow]

Is the lohgest sentence the sentence that has the greatest number of words within it or that has the longest length?

[TFFBRAIN]

the sentence that has the greatest number of words

[TFFBRAIN]

i need a program that asks the user to enter sentences until he enters "this is the end". and then shows the sentence entered that has the greatest number of words

[vlad from moscow]

You can use standard function strtok to split a sentence into words.
Or you can write two macros or inline functions something as SkipSpaces and ExtractWord to count the number of words in a sentence.

EDIT: For example

#define SkipSpaces( p ) while ( isblank( *p ) ) ++p
#define ExtractWord( p ) while ( *p && !isblank( *p ) ) ++p
#define IsEmpty( p ) ( *p == '\0' )

Then to determine the number of words you can use the following loop

int count = 0;
char *p   = st;

while ( !IsEmpty( p ) )
{
   SkipSpaces( p );
   if ( !IsEmpty( p ) )
   {
      count++;
      ExtractWord( p );
   }
}

[vlad from moscow]

Here is a tested code

#include <stdio.h>
#include <string.h>

/*	MS VC++ 2010 does not support C standard function isblank.
	So I changed it to explicit using space and tab symbols
*/
#define	SkipSpaces( p ) while ( *p == ' ' || *p == '\t' ) ++p
#define	ExtractWord( p ) while ( *p && *p != ' ' && *p != '\t' ) ++p
#define	IsEmpty( p ) ( *p == '\0' )


int main( void )
{
	char s[] = "This is some sentence.";

	size_t count = 0;
	char *p = s;

	while ( !IsEmpty( p ) )
	{
		SkipSpaces( p );
		if ( !IsEmpty( p ) )
		{
			count++;
			ExtractWord( p );
		}
	}

	printf( "There are %u words in the sentence", count );
}

The ouput is

There are 4 words in the sentence

And this code was tested at www.ideon.com

#include <stdio.h>
#include <string.h>
#include <ctype.h>

#define	SkipSpaces( p ) while ( isblank( *p ) ) ++p
#define	ExtractWord( p ) while ( *p && !isblank( *p ) ) ++p
#define	IsEmpty( p ) ( *p == '\0' )


int main( void )
{
	char s[] = "This is some sentence.";

	size_t count = 0;
	char *p = s;

	while ( !IsEmpty( p ) )
	{
		SkipSpaces( p );
		if ( !IsEmpty( p ) )
		{
			count++;
			ExtractWord( p );
		}
	}

	printf( "There are %u words in the sentence", count );
    
	return 0;
}

Of course it would be better to substitute these two statements

	char *p = s;

	while ( !IsEmpty( p ) )

for this one

for ( char *p = s; !IsEmpty( p ); )