How can I show this output on screen?

[Silver Falcon]

I want to write a program that makes this output to appear on screen using for-loop :

0        0
         1
         2
         3
         4
         5

1        0
         1
         2
         3
         4
         5

2        0
         1
         2
         3
         4
         5

3        0
         1
         2
         3
         4
         5 

I can't seem to make the correct logic/engine of this nested loop. Anyone help.

[condor]

Have you tried? Let's see the code ...

[Silver Falcon]

Yep I have tried but it comes like this :

0        
         0
         1
         2
         3
         4
         5

1        
         0
         1
         2
         3
         4
         5

2       
         0
         1
         2
         3
         4
         5

3        
         0
         1
         2
         3
         4
         5

And not like :

0        0
         1
         2
         3
         4
         5

1        0
         1
         2
         3
         4
         5

2        0
         1
         2
         3
         4
         5

3        0
         1
         2
         3
         4
         5

Here is the code :

#include <iostream>

using namespace std;

int main()
{
	for (int a=0 ; a<=3 ; a++)
	{
		cout<<a<<endl;
		for (int b=0; b<=5 ; b++)
		{
			cout<<"         "<<b<<endl;
		}
	}

	return 0;
}

Please let me know of any modifications.

[Mats]

You need to get rid of the endl after a.

Think about this logically. You want to output a and then output b and then AFTER THAT have a newline. Try your putting your newline in a place that achieves this.

//output a
//output b
//newline
//output b
//newline
//etc

[condor]

Good! Excellent! Try this:

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27

#include <iostream> using std::cout; int main() { for(int a = 0; a < 4; ++a) { cout << a; for(int b = 0; b < 6; ++b) { if(b == 0) cout << " " << b << '\n'; else cout << " " << b << '\n'; } cout << "\n"; } }

0 0 1 2 3 4 5 1 0 1 2 3 4 5 2 0 1 2 3 4 5 3 0 1 2 3 4 5

[Silver Falcon]

oh yes finally i have found out that.
it's something like this :

#include <iostream>

using namespace std;

int main()
{
	for (int a=0 ; a<=3 ; a++)
	{
		cout<<a;
		for (int b=0; b<=5 ; b++)
		{
			cout<<"\t"<<b<<endl;
		}
		cout<<endl;
	}

	return 0;
}

But one thing that i still can't understand is with "\t". This \t means some amount of spaces(tab) 4 or 5 i don't remember. But when I replace this with manual " "(spaces in between), it gives me slightly misplaced output.

Example :-
Code:

#include <iostream>

using namespace std;

int main()
{
	for (int a=0 ; a<=3 ; a++)
	{
		cout<<a;
		for (int b=0; b<=5 ; b++)
		{
			cout<<"     "<<b<<endl;
		}
		cout<<endl;
	}

	return 0;
}

Output:

0         0
         1
         2
         3
         4
         5

1         0
         1
         2
         3
         4
         5

2         0
         1
         2
         3
         4
         5

3         0
         1
         2
         3
         4
         5

Why this happens?

[condor]

Or, slightly changed:

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27

#include <iostream> #include <iomanip> using std::cout; using std::setw; int main() { for(int a = 0; a < 4; ++a) { for(int b = 0; b < 6; ++b) { if(b == 0) cout << a << setw(8) << b << '\n'; else cout << setw(9) << b << '\n'; } cout << "\n"; } }

0 0 1 2 3 4 5 1 0 1 2 3 4 5 2 0 1 2 3 4 5 3 0 1 2 3 4 5

[Silver Falcon]

Thanks condor, that was impressive and simple ( what a dumbass i had been). But could you please answer my question mentioned above?

[condor]

Yes.
line 9 in your last code cout << a occupies a space and when "appears" b from line 12 will be shifted. Then loop with b goes on without that "a" till the end of the loop b and so on.

EDIT: If all OK please mark this thread as Solved.

[Silver Falcon]

But why this doesn't happen with "\t" ? Do you know that?

[condor]

cout << "\t"; counts the occupied spaces from the very beginning of the line ignoring the presence of that "a".

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27

#include <iostream> using std::cout; int main() { for(int a = 0; a < 4; ++a) { cout << a; for(int b = 0; b < 6; ++b) cout << '\t' << b << '\n'; cout << '\n'; } }

0 0 1 2 3 4 5 1 0 1 2 3 4 5 2 0 1 2 3 4 5 3 0 1 2 3 4 5

[Silver Falcon]

Okay. My problem is solved. Thanks man. Have a nice day!