Passing to Function - Unspecified Array

[weathers2015]

Hello, I am working on a project, but have found my self stuck on one section.

I have a function called:
arrayToInteger(int digits[], int length)

which as the title suggests, it takes the integer values in each cell of the array and joins them together to make a single integer. So an array of [1|0|1] becomes the integer 101.

The problem I am facing is that i need to make the "int digits[]" become a generic term so that I can pass in any array I want. I have set it up so I pass the array called "digits[]" into the function which works great, but I can't pass an array called "descend[]" into the function when I call it the second time.

Can you guys help me with this?

So what I'm looking for is arrayToInteger(int (any array)[], int length)

Here is the code:

int arrayToInteger(int digits[], int length )
{
std::stringstream ss;
for (unsigned i = 0; i < length; ++i)
ss << digits[i];

int integer = 0;
ss << integer;
cout << integer;
return integer;
}

Thank you.

[helios]

Huh?

int foo[6];
int bar[5];
//...
int n = arrayToInteger(foo, 6);
int m = arrayToInteger(bar, 5);

[weathers2015]

Here is the function:

int arrayToInteger(int digits[], int length )
{
std::stringstream ss;
for (unsigned i = 0; i < length; ++i)
ss << digits[i];

int integer = 0;
ss << integer;
cout << integer;
return integer;
}

I want to make it so it will accept any array not just digits[].

What you posted is basically what I want in my main function.

[helios]

That function does accept any array.

[weathers2015]

Nevermind, I'm an idiot. Haha this works just fine, it was another function that was messed up.

Thank you for the quick reply