Can't get output to display 8 numbers per line

[LullaBelle]

I've literally been trying to figure this out all night, but I can't seem to get my output to display 8 numbers per line, so 8 columns of numbers. I can only get them to list back to back and wrap around to the next line.

Sorry in advance if my code doesn't come out correctly. Whenever I go to format it, it shows "javascript:tx('code')" and I can't seem to get the preview to show anything to see if I'm doing it right.

// Program prompts user to enter integer from 1-99
// and then using a loop construct, print values
// starting from the value entered to 100.
// In addition, print 8 numbers per line.
#include <iostream>
using namespace std;

int main()
{
    int minNumber;
    int maxNumber = 100;

    cout << "Enter a number between 1 and 99: ";
    cin >> minNumber;
    cout << endl;

    for ( int number = minNumber; number <= maxNumber; number++)

        cout << number << " ";

    cout << "\n";
    return 0;
}

[SakurasouBusters]

int k = 0;
    for ( int number = minNumber; number <= maxNumber; number++)
        {
                cout << number << " "; if(++k == 8) {cout << endl; k = 0;}
        }

[LullaBelle]

Thank you for that, but can you explain? There's nothing in our textbook that describes doing this.

[SakurasouBusters]

https://msdn.microsoft.com/en-us/library/dy3d35h8.aspx

[LullaBelle]

Yes, I understand the rules of the de- and increment operators. I'm talking about how the if statement is set up. Why are you initializing a new variable, etc..

Yes, these are newbie questions, but I'm a newbie. Instead of just having an answer given to me, I'd like to understand what's happening.

[SakurasouBusters]

So your teacher doesn't permit you to declare any variables of your choice?

[LullaBelle]

We can, but I like to keep mine relevant to what the program is doing, which is why I was confused about k. It just seems so out of place.

[SakurasouBusters]

Can you even understand this?
1.
if(++k == 8)

2.
{cout << endl; k = 0;}

3.
if(++k == 8)

4.
{cout << endl; k = 0;}

5.
if(++k == 8)

6.
{cout << endl; k = 0;}

7.
if(++k == 8)

8.
{cout << endl; k = 0;}

etc

Why? These are very very simple statements.

[LullaBelle]

Well excuse me...

Don't understand why everyone in this community has to say something in a condescending tone. We all start from somewhere. It takes me a little longer to grasp something. Sue me.

[SakurasouBusters]

How long have you been learning C++?
Depending on that, I can teach you line by line, step by step.

If you look closely, these are very simple statements.
1.
int k = 0; // Assignment statement

2.
if(++k == 8) // If statement, prefix-increment, comparison statement

3.
cout << endl; // Basic std::cout statement

4.
k = 0; // Assignment statement

Have you learned if-statement?

[LullaBelle]

I started a little less than a month ago. Last Wednesday, we started working on all the if-statements and this Monday we started the while and for loops.

Everything in my original code, I understand. I understand relational, arithmetic, and logical operators. I understand initializing a variable.

[Duthomhas]

@SakurasouBusters
Your tone is fairly condescending. JSYK.

A new variable is not strictly necessary, but it is useful. Compare:

1 2 3 4 5 6 7 8 9 10 11 12 13

for (int n = minvalue; n <= maxvalue; n++) { // Print the number (and some space) cout << n << " "; // Check to see if we have printed 8 numbers... if ((n - minvalue) % 8) == 7) // yes: print a newline cout << "\n"; }

int columns = 0; for (int n = minvalue; n <= maxvalue; n++) { // Print the number (and some space) cout << n << " "; // Check to see if we have printed 8 numbers... if (++columns == 8) { // yes: print a newline cout << "\n"; columns = 0; // and reset column counter } }

As a side note, there is a potential maximum value issue with a loop terminating on <=; I would have written it with a different loop:

if (minvalue <= maxvalue)
{
  int columns = 0;
  int n = minvalue;
  do {
    cout << n 
         << ((++columns == 8) ? "\n" : " ");
    columns %= 8;
  } \
  while (n++ < maxvalue);
}

You may also want to pay attention to the final newline.

Hope this helps.

[LullaBelle]

@Duoas Thank you, I really appreciate it. All I was wanting was a breakdown of what was going on. This helped a lot.