creating vector or array with different names in a loop

[mehdicpp]

Hi
I'm trying to loop this
for(int i = 0; i <3; i++){
string a = "desc";
char counter1[10];
itoa(i,counter1,10);
a += counter1;// the name that should be used insted of
vector <double> a;
}
out put vectors with names of desc0, desc1 and desc2
how can I do that
thank you in advance

[Thomas1965]

You can't do that. Names of variables must be known at compile time.

[gunnerfunner]

One way to have looping variable dependent vector identifiers might be to use a std::vector<std::unique_ptr<std::vector<double>> such that each element of this vector refers to a unique std::vector<double>:

#include <iostream>
#include <memory>
#include <vector>
#include <utility>

constexpr auto SIZE = 3;

int main ()
{
   std::vector<std::unique_ptr<std::vector<double>>> desc;
   for (auto i = 0; i < SIZE; ++i)
   {
       std::cout << "Enter size of vector #" << i + 1 << ": ";
       size_t n{};
       std::cin >> n;
       std::vector<double> v{};
       for (auto j = 0; j < n; ++j)
       {
           std::cout << "Enter element #" << j + 1 << " of vector# " << i + 1 << ": ";
           double num{};
           std::cin >> num;
           v.push_back(num);
        }
       desc.push_back(std::move(std::make_unique<std::vector<double>>(v)));
       v.clear();
   }
   for (auto i = 0; i < SIZE; ++i)
   {
       for (auto j = 0; j < (*desc[i]).size(); ++j)
       {
           std::cout << (*desc[i])[j] << " ";
       }
       std::cout << "\n";
   }
}

[mehdicpp]

thanks a lot.
this would get the job done.