Aligning Numbers

[JarJarz]

I am converting a number given by the user to hyperbolic functions, I have the code written I just need help aligning the numbers. Everything is fine until I enter a negative number, or .01

What would I have to add to these cout statements?

double x;
cout << endl;
cout << "Enter a value for x" << endl;
cin >> x;
cout << endl;
cout << "Converting: " << x << endl;
cout << endl;

double e = 2.71828182846;
double minus = pow(e, x) - pow(e, -x);
double plus = pow(e, x) + pow(e, -x);

cout << setprecision(10) << "sinh(" << x << ") = " << minus / 2 << endl;
cout << setprecision(10) << "cosh(" << x << ") = " << plus / 2 << endl;
cout << setprecision(10) << "tanh(" << x << ") = " << minus / plus << endl;
cout << setprecision(10) << "coth(" << x << ") = " << plus / minus << endl;
cout << setprecision(10) << "sech(" << x << ") = " << 2 / plus << endl;
cout << setprecision(10) << "csch(" << x << ") = " << 2 / minus << endl;

[lastchance]

#include <iostream>
#include <iomanip>
#include <string>
#include <cmath>
using namespace std;


void output( string func, double x, double result )
{
   cout << func << "(" << x << ") = " << fixed << setprecision( 10 ) << setw( 16 ) << result << endl;
   cout.unsetf( ios::fixed );
}


int main()
{
   double x;
   cout << "Enter a value for x: ";
   cin >> x;
   cout << "Converting: " << x << "\n\n";
   
   double e = 2.71828182846;
   double expx = pow( e, x );    // or just use:    expx = exp( x );
   double minus = expx - 1.0 / expx;
   double plus  = expx + 1.0 / expx;
   output( "sinh", x, minus / 2.0   );
   output( "cosh", x, plus  / 2.0   );
   output( "tanh", x, minus / plus  );
   output( "coth", x, plus  / minus );
   output( "sech", x, 2.0   / plus  );
   output( "csch", x, 2.0   / minus );
}

Enter a value for x: -1
Converting: -1

sinh(-1) =    -1.1752011936
cosh(-1) =     1.5430806348
tanh(-1) =    -0.7615941560
coth(-1) =    -1.3130352855
sech(-1) =     0.6480542737
csch(-1) =    -0.8509181282

Enter a value for x: 0.01
Converting: 0.01

sinh(0.01) =     0.0100001667
cosh(0.01) =     1.0000500004
tanh(0.01) =     0.0099996667
coth(0.01) =   100.0033333111
sech(0.01) =     0.9999500021
csch(0.01) =    99.9983333527

At some point you will need to use "scientific" rather than "fixed" and adjust width accordingly. These exponential-based functions have a huge range.