Cant print out pattern

#include <iostream>
using namespace std;
void pattern(int n, int shift);
int main()
int n;
cout << "Please enter an integer that is a power of two: ";
cin >> n;
pattern(n, 0);
//{hey(n, 0);}
return 0;
void pattern(int n, int shift)
int i;
if(n == 2)//print(n/2,col)
for(i = 0; i <= shift; i++)
cout << " ";
cout << "a" << endl;
pattern(n/2, shift);
pattern(n/2, shift + n/4);
for (i = 0; i < n; i++)
cout << "a ";

Hi all I am trying to print out this pattern but can't seem to print out the a pattern, the "-" is for illustration purposes. Please help me thankyou
Last edited on
if(n=2) should probably be if(n==2)

What's the pattern rule? How do you get from one step to the next?
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