Not using namespace?

[smcguffee]

Hi,
I have a class where I am deliberately naming some of the member functions with the same name as common math library functions such as log, but using different types such as string log(string);
Keeping the names identical between the math library and the class I'm writing is essential for a macro I'm using.
My problem is that inside my member functions I want to call on the math library functions, but the compiler seems to only look in the namespace of the class. I say namespace loosely because I mean in the class space even though I didn't create a namespace otherwise.
For example, if my class were called myclass, then here is an example to illustrate my problem:

string myclass::log(string in)
{
     string out;
     double inD=myFunc(in);
     double outD=log(inD); // At this point the compiler has an issue:
                           // It can't seem to find the math library.
                           // It says:
                           //"error: no suitable conversion function 
                           //from "std::string" to "double" exists
     out=myFunc2(outD);
}

I can get around this by adding:

extern double log(double);

but I don't think I should have to.
Is there a way to say "not using namespace myclass?"
Thanks,
Sean

[zwA4jE8b]

:: is the namespace resolution operator.
the math functions are in the std namespace

std::log();
std::sin();

[smcguffee]

I'm not sure why, but that isn't working for me:
my compiler says, "error: 'log' is not a member of 'std'"

[Moschops]

Are you including math.h or cmath?

[smcguffee]

math.h
just using ::log seems to work though.
Thanks!

[Moschops]

math.h does not use the std namespace. It's the C header. cmath is the C++ header.