switch menu, keep the program running?

[navlelo]

-- removed since resolved

[LB]

Switch-case statements are not do-while loops. That while loop at the end of your program is what stops the code in its tracks. Though, you could easily make it into a do-while loop, which is probably what you wanted.

[naderST]

Declare the data you don't wanna lose outside main() and then at the end of de main function call main function again!

[LB]

naderST wrote:

Declare the data you don't wanna lose outside main() and then at the end of de main function call main function again!

I highly recommend not doing this. It's bad coding practice, it wastes memory, and it clutters the global scope. Did I mention that I don't recommend doing it? ;)

[naderST]

L B wrote:

I highly recommend not doing this.

Why? well, he can write a function called menu() and then call that function...

[LB]

Yes, he could do that, but for persistent data in this case is is better to use a while loop. ;)

[naderST]

Yes, he could do that, but for persistent data is is better to use a while loop. ;)

Thanks is good to know that!

[navlelo]

my initial program had do while and if-else nesting for all choices, but it ended up just printing my menu again without going thru the "cases" properly then. switch goes thru them properly, but then I get stuck without a chance to work on it further... I'll try do while again later, but I'm a bit skeptic to use it :)

[navlelo]

ow sorry, I misunderstood, I got it working now. nesting the switch inside the do-while did the trick, thanks guys :D