Decimal to Binary number

[arefe]

Here is a program to convert decimal to binary-

#include <iostream>
 
using namespace std;
 
void binary(int);
 
int main(void) {
    int number;
 
    cout << "Please enter a positive integer: ";
    cin >> number;
    if (number < 0)
        cout << "That is not a positive integer.\n";
    else {
        cout << number << " converted to binary is: ";
        binary(number);
        cout << endl;
    }
}
 
void binary(int number) {
    int remainder;
 
    if(number <= 1) {
        cout << number;
        return;
    }
 
 
    remainder = number%2;
    binary(number >> 1);
    cout << remainder;
}

I'm in a bit difficulty to understand the function binary().

Say, I would like to convert Decimal 11 to binary number. binary(number >> 1) uses bit-wise operation and generates values 5,2 and 1.For the number 11, its goes to the binary ()function recursively with with 5 then, 2 and 1. My question is then it should print the binary as 1101 with reminder output, right ? But, its prints the true value 1011. Also, after the term
remainder = number%2, every-time due to recursion its again go in the top to use the function. How the cout << remainder; able to print ?

The answer will help me a lot. Thanks :)

[JokerDan]

Wow, i just started to try and accomplish the same goal.
Slightly different method though... Im going to keep working on mine and get back to you, good luck!

[arefe]

Haha.. Cool. Very less reply today. Is this for weekend and people are still sleeping ?

[nooblet]

why are you using recursion ??? can be done without ...

[jumper007]

Recursion is important when you intend to use the same function repeatedly, such as in a game.

Coming back on topic, I can see an error.

int main(void) /* this declaration is not good for what you try to achieve 
                                     (from my knowladge) */

If I'm right you just told the c++ compilator that the main function will return void (=nothing).

[jumper007]

Also, dont use this in function.

cout << variable;

Instead, you could use:

return variable;

But if you will use return variable; you will need to declare the current function with a specific type, so not void. Declaring the function as void, you cannot return anything. So that is another error on your line 26. Let me give you an example:

int binary(int number) {
    int remainder;
 
    if(number <= 1) {
        return number;
    }
 
 
    remainder = number%2;
    binary(number >> 1);
    return remainder;
}

[arefe]

Thanks all.