### Reverse and sort arrays

Hi,

How can I reverse my output array? In other words if user enters 1,8,3,10,5 I wan t them to appear as 5,10,3,8,1.

Finally, how can I sort them out highest to lowest?

 ``123456789101112131415161718192021222324252627`` ``````#include #include #include #include using namespace std; int main() { const int SIZE = 5; // must be a constant variable int myArray[SIZE]; cout << "Enter 5 Numbers: "<< endl; for(int i = 0; i < SIZE; i++) { cin >> myArray[i]; } cout << "Your 5 numbers are: "; for(int i = 0; i < SIZE; i++) { cout << myArray[i] << " "; } //system("pause"); // pause system return 0; }``````

As always thanks a lot!
I already tried these functions, but I cannot make it work. I'm new to arrays.
Since you are new to arrays, I bet you tried to use reverse like this: `reverse (array[0], array[n])`, or something like that.
But, if you read the reference you'll see that both use "iterators", and basicly what those are, is pointers. So, use it like this:
 ``123456789101112131415161718192021222324252627`` ``````#include #include #include #include using namespace std; int main() { const int SIZE = 5; // must be a constant variable int myArray[SIZE]; cout << "Enter 5 Numbers: "<< endl; for(int i = 0; i < SIZE; i++) { cin >> myArray[i]; } reverse(myArray, myArray+SIZE); cout << "Your 5 numbers are: "; for(int i = 0; i < SIZE; i++) { cout << myArray[i] << " "; } //system("pause"); // pause system return 0; }``````

As you can see, i used myArray without the bracket operator. That meant i used a pointer(aka "iterator") to the beggining, and one space after the end of the array.
Awesome! Thanks a lot

How can I sort them?
same thing, just replace the "reverse" with "sort"
Last edited on
Thanks a lot for your help!
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