string storing in integer array!
| sibendudey (8) |  |
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what is the output? int i1[]={"\12345s\n"}; printf("i1=%d\n",sizeof(i1)); | |
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| Peter87 (3908) | |
| The output is a compiler error. It doesn't make sense to store a string in an array of ints. What are you trying to accomplish? | |
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| sibendudey (8) | |
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iam trying to solve a question.. the question is find the output of the printf statement!!! | |
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| iantac (39) | |
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if I correct the code of yours
the output if i1=4 since you can't do {"\12345s\n"} in a integer array
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Last edited on
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| viliml (791) | |
| Silly question: did you ever try to compile it to find the answer? Yes, l know its stupid and compleaty ridiculous, but did it ever occur to you? | |
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