Vowel Counter

[pizzlefank]

Hello I am new. I need to write a program using at least one while loop to count and display the amount of vowels in a user input string. This is what I have so far.

#include <iostream>
#include <cmath>
using namespace std;
int main()
{
int acounter(0); // Create counters for each vowel
int ecounter(0);
int icounter(0);
int ocounter(0);
int ucounter(0);


char c; // Set variable c as a character

cout << "Input: "; // Let user declare c
cin >> c;

while (c) // Run loop to count vowels
{
if (c == 'a'|| c== 'A')
{
acounter = acounter + 1;
}
if (c == 'e'|| c== 'E')
{
ecounter = ecounter + 1;
}
if (c == 'i'|| c== 'I')
{
icounter = icounter + 1;
}
if (c == 'o'|| c== 'O')
{
ocounter = ocounter + 1;
}
if (c == 'u'|| c== 'U')
{
ucounter = ucounter + 1;
}

}
cout << acounter;
cout << ecounter;
cout << icounter;
cout << ocounter;
cout << ucounter;
return 0;
}

I don't have a clue where to go. Please help a newbie. Explanation would be helpful. Thanks

[Smac89]

get word from user

if (toupper (word[i]) == 'A' || toupper (word[i]) == 'E' || toupper (word[i]) == 'I' || toupper (word[i]) == 'O' || toupper (word[i]) == 'U')

increment counter

[vlad from moscow]

This

char c; // Set variable c as a character

cout << "Input: "; // Let user declare c
cin >> c;

while (c) // Run loop to count vowels
{

is invalid code. I think you have to use a character array instead of one character.