return a struct pointer from a void function() and print

[RD7]

i need to return a struct pointer dynamically allocated inside a function call void function() which is done using 'out parameters' in following code

struct my_struct 
{
int x;
}
void my_function( my_struct** result )
{
   my_struct* x = new my_struct{ 10 };
   //...
   *result = x;
}

now i have a doubt, so if i want to print the return value from struct pointer, should i need to print it in the void function() or in the caller the function

[Peter87]

Both is possible.

// from within the function:
std::cout << x->x << std::endl;
// or
std::cout << (*result)->x << std::endl;

// from the caller of the function:
my_struct* p;
my_function(&p);
std::cout << p->x << std::endl;

[RD7]

@Peter87 great it worked

[RD7]

@Peter87
i have another paradigm where i need to print a pointer of type struct which gets the value dynamically in each iteration and also print a defrenced struct member on each iteration.

struct my_struct
{
int x;
int y;
}
void function(){

my_struct* a=tls.get() // some values will be assigned dynamically to this pointer from other part of function.

my_struct* data = new thread_data;
data->x=1 //which will get updated according the iterations and conditions
data->y=2 //which will get updated according the iterations and conditions

}

now i need to print the values of a,x,y in the caller function. How to print those values. some what like

printf("a=%lx x=%i y=%i\n", a,x,y);

can you please give me some ideas or how to proceed? thanks alot