C++ counting arrays output help?

[yunyang21]

Hi, I was wonding if anyone could please help me with my programming. I got most of my programming down. I just need help with my output. Currently I have:
Enter a number:
9 < ==the amount I want
Enter 9 numbers:
1 1 2 9 3 2 5 1 9 <== numbers that I inputed

1 happened 0 times.
1 happened 0 times.
1 happened 0 times.
2 happened 0 times.
2 happened 0 times.
3 happened 0 times.
5 happened 0 times.
9 happened 0 times.
9 happened 0 times. < == my current output

But what I really want is:
1 happened 3 times.
2 happened 2 times.
3 happened 1 times.
5 happened 1 times.
9 happened 2 times. < == expected output.

Can anyone please help me.
my code so far is

double number[1000];
int n;
int i;
int smallest;
int j;
int tempvalue;

for(i = 0; i < 1000; i = i + 1){
number[i] = 0;
}
cout << "Enter a number.\n";
cin >> n;
cout << "Enter " << n << " numbers:\n";
i = 0;
while(i < n){
cin >> number[i];
i = i + 1;
}
i = 0;
while(i < n-1){
smallest = i;
for(j=i+1;j < n; j = j+1){
if (number[smallest] > number[j]){
smallest = j;
}
}
tempvalue = number[i];
number[i] = number[smallest];
number[smallest] = tempvalue;
i = i + 1;
}
for(i = 0; i < n; i = i + 1){
cout<< number[i] << " happened " << number[smallest] << " times.\n";
}

[vlad from moscow]

This code is already invalid

i= 0;
while(i < n-1){

Let assume that n = 1 then you will have

while ( 0 < 0 )

so this loop will be executed never.