### Can't total up the results calculted...

i am doing a sales commission program to run a counter on the commission calculated, but the answers can't show on the counter

here's what i've done so far:
#include <iostream>
#include <iomanip>
#include <cmath>

using namespace std;

int main ()
{
int i;
double salary = 0;
double gross[10];
int count1 = 0;
int count2 = 0;
int count3 = 0;
int count4 = 0;
int count5 = 0;
int count6 = 0;
int count7 = 0;
int count8 = 0;
int count9 = 0;
int numCounter = 0;

for (i=0; i<10; i++)
{
cout << "\nPlease enter the gross sales that you have made for the week: " << endl;
cin >> gross[i];

salary = 200 + (0.0900 * gross[i]) ;

cout << "\nYour commission for the week: " << salary << endl;
}

numCounter = 0;
while(numCounter <= 10)
{
salary = gross[numCounter];

salary = 200 + (0.0900 * gross[i]) ;

if (salary >= 200 && salary <= 299)
count1 += 1;

else

if (salary >= 300 && salary <= 399)
count2 += 1;

else

if (salary >= 400 && salary <= 499)
count3 += 1;

else

if (salary >= 500 && salary <= 599)
count4 += 1;

else

if (salary >= 600 && salary <= 699)
count5 += 1;

else

if (salary >= 700 && salary <= 799)
count6 += 1;

else

if (salary >= 800 && salary <= 899)
count7 += 1;

else

if (salary >= 900 && salary <= 999)
count8 += 1;

else

if (salary >= 1000)
count9 += 1;

else

cout << " " << endl;

numCounter += 1;
}

cout << "(a) \$200 - \$299 :" << count1 << endl;
cout << "\n(b) \$300 - \$399 :" << count2 << endl;
cout << "\n(c) \$400 - \$499 :" << count3 << endl;
cout << "\n(d) \$500 - \$599 :" << count4 << endl;
cout << "\n(e) \$600 - \$699 :" << count5 << endl;
cout << "\n(f) \$700 - \$799 :" << count6 << endl;
cout << "\n(g) \$800 - \$899 :" << count7 << endl;
cout << "\n(h) \$900 - \$999 :" << count8 << endl;
cout << "\n(i) \$1000 and over :" << count9 << endl;
}
 ``12`` ``````salary = 200 + (0.0900 * gross[i]) ; `````` `warning: array subscript is above array bounds [-Warray-bounds]`
Please take a pensil and a paper and calculate what will be the value of the expression salary = 200 + (0.0900 * gross[i]) ;
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