Basic Algebra (Making Equations Equal) - Need Help

[RecoJohnson]

I forget the important stuff about fractions.

Could someone please explain in detail how to get the answer to this question?
http://i.imm.io/ofLN.jpeg
Would be greatly appreciated!

[NGen]

Set the fractions on both sides of the equation to have equal denominators. In this case, 6 works. Once you've done this, you can practically get rid of the denominators altogether - the numerators become the only parts of the equation. Then you can just solve like normal.

(x-2)/2 - (2x+7)/3 = (-5)/2
- Original Equation

(3(x-2))/(3(2)) - (2(2x+7))/(2(3)) = (3(-5))/(3(2))
- Multiplying the numerators and denominators of each term appropriately

(3x-6)/6 - (4x+14)/6 = (-15)/6
- As a result of the multiplication, all terms have a denominator of 6

(3x-6) - (4x+14) = -15
- Got rid of the denominators, now just solve like normal.

3x-6 - 4x-14 = -15

-x - 20 = -15

-x = 5

x = -5

Note: The second step just looks convoluted because I tried to write it all out on one line.

[man0987]

1.Mulitply every term by 6.
2.Resulting Expression:
3(x-2)-2(2x+7)=(-15)
or 3x-6-4x-14= (-15)
or -20-x+15=0
or x=(-5).